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Forces and Newton's Laws · Lesson 3 of 5

The Second Law

16 min read3 ideas4 checks2 figures to playBy Asheshanand Acharya
What you will learn 0 / 3
Force mass and acceleration
Maths you need
Look around
The empty trolley and the full one

At a railway station a porter pushes a luggage trolley. When the trolley is empty, a light push sets it moving quickly. When it is loaded with suitcases, the same push hardly gets it going. Two porters pushing the loaded trolley together get it moving as briskly as one porter moved the empty one.

you will be able to say exactly how much faster the empty trolley speeds up, from one law and two numbers.

What a net force does

The first law says that a net force changes the velocity. It does not say by how much. The answer comes from experiment. Push a trolley on a smooth floor with a steady force and measure its acceleration. Then push the same trolley with twice the force. Then load the trolley so that its mass is doubled, and push again.

One force and two equal forces on a trolleyTwo trolleys of mass 2 kilograms start from rest on two tracks. The upper one is pushed by one force of 2 newtons and accelerates at 1 metre per second squared. The lower one is pushed from behind and pulled at its handle by two equal forces of 2 newtons and accelerates at 2 metres per second squared, covering twice the distance in every interval. In the second state a 2 kilogram load sits on the lower trolley and the two keep pace. Dots mark each trolley every half second.flat trolley / laboratory carthand, pushing to the right, forearm cropped (line art). Pushing face at (1.00, 0.52) of the box.hand, fist gripping and pulling, forearm cropped (line art)hand, pushing to the right, forearm from the left (line art). Pushing face at (1.00, 0.48) of the box.hand, fist gripping and pulling, forearm to the right (line art) 2 kg F F F upper: a = 1.0 m/s² lower: a = 2.0 m/s²
Fig 3.1Press play. Both trolleys have mass \(2\,\text{kg}\). The upper one is pushed by one force \(F = 2\,\text{N}\). The lower one is pushed and pulled by two equal forces, \(2F\) in all. The dots mark each trolley every half second. Then switch state: a load doubles the lower trolley's mass, and the two trolleys keep pace.

Compare the dots in Fig 3.1. In the first state the lower trolley covers twice the distance of the upper one in every interval. Its acceleration is twice as large, \(2\,\text{m/s}^2\) against \(1\,\text{m/s}^2\). Twice the force gives twice the acceleration. In the second state the lower trolley carries a load that doubles its mass to \(4\,\text{kg}\). Now twice the force on twice the mass gives the same acceleration as the upper trolley.

So the acceleration is proportional to the net force, \(a \propto F\), and inversely proportional to the mass, \(a \propto 1/m\). Put together, \(a \propto F/m\). The unit of force is chosen so that the constant of proportionality is exactly one. That choice gives the second law in its familiar form.

\[ F = ma \]

The newton

The newton is the net force that gives a body of mass \(1\,\text{kg}\) an acceleration of \(1\,\text{m/s}^2\). So \(1\,\text{N} = 1\,\text{kg·m/s}^2\). A newton is a small force. An apple of mass \(100\,\text{g}\) has a weight of about \(1\,\text{N}\). Lifting a one-litre bottle of water needs about \(10\,\text{N}\).

law 1.3
Newton's second law of motion

The acceleration of a body is directly proportional to the net force acting on it, is inversely proportional to its mass, and is in the direction of the net force.

Mass measures inertia

A loaded trolley is harder to speed up than an empty one. It is also harder to stop. The second law turns this into a number. The mass of a body measures its inertia: the larger the mass, the smaller the acceleration for a given net force. Mass is a scalar, measured in kilograms, and it is the same wherever the body is taken.

ExampleAn auto-rickshaw pulls away

An auto-rickshaw with its passengers has a mass of \(600\,\text{kg}\). It starts from rest and reaches \(9\,\text{m/s}\) in \(6\,\text{s}\) on a straight level road. Find the net force on it, assuming the acceleration is uniform.

Reveal one step at a time and finish the rest yourself.
Checkpoint · numericUnanswered

A net force of \(12\,\text{N}\) acts on a trolley of mass \(4\,\text{kg}\). What is its acceleration in \(\text{m/s}^2\)?

m/s²± 2 %
CheckpointUnanswered

The same net force acts on two bodies. Body B has half the mass of body A. How does the acceleration of B compare with that of A?

Second law as a vector
Maths you need

The second law is a vector law

Force and acceleration are both vectors. The second law says more than "the sizes are proportional". It says that the acceleration points in the same direction as the net force. Several forces may act on the body; the law uses their vector sum.

\[ \sum \vec F = m\,\vec a \]

The mass \(m\) is a positive scalar, so multiplying \(\vec a\) by \(m\) changes its length but not its direction. The acceleration is always along the net force. It need not be along the velocity. A ball thrown upward has an upward velocity and a downward acceleration, because the net force on it, its weight, points down.

One law per axis

A vector equation holds component by component. Choose two perpendicular axes, \(x\) and \(y\). The \(x\) components of the forces add up to \(m a_x\), and the \(y\) components add up to \(m a_y\). This is the same idea as the independence of perpendicular motions in the last unit. Each axis gets its own equation, and the two are solved together.

RememberNewton's second law
\[ \sum \vec F = m\,\vec a, \qquad \sum F_x = m a_x, \qquad \sum F_y = m a_y \]
Holds whenin an inertial frame, for a body of constant mass; \(\sum \vec F\) is the vector sum of all the forces on the body.
Symbols\(\sum \vec F\) net force on the body, \(m\) its mass, \(\vec a\) its acceleration, \(x, y\) two perpendicular axes of your choice
Units\(F\) in N, \(m\) in kg, \(a\) in m/s²
Two forces and the acceleration along their sumA puck of mass 2 kilograms on smooth ice is pulled 3 newtons east and 4 newtons north. Dashed lines complete the rectangle. The net force, 5 newtons, is the diagonal at 53 degrees north of east. The acceleration arrow, 2.5 metres per second squared, is parallel to the net force.ball (shaded) 3 N 4 N ΣF a, along ΣF 53° east north a = ΣF / m = 5 / 2 = 2.5 m/s²
Fig 3.2Two forces act on a puck of mass \(2\,\text{kg}\) on smooth ice: \(3\,\text{N}\) east and \(4\,\text{N}\) north. Their vector sum is \(5\,\text{N}\) at \(53°\) north of east. The acceleration, \(2.5\,\text{m/s}^2\), points exactly along that sum, and along neither force alone.
ExampleTwo forces on a puck

A puck of mass \(2\,\text{kg}\) rests on smooth ice. Two strings pull it horizontally, one with \(3\,\text{N}\) towards the east and one with \(4\,\text{N}\) towards the north. Find the size and direction of its acceleration.

Try it on paper first. The solution is one tap away when you are ready.
CheckpointUnanswered

A stone thrown upward is still rising. Air resistance is neglected. What is the direction of its acceleration?

Mass and weight

Mass against weight

In daily speech we "weigh" a bag of sugar and give the answer in kilograms. Physics keeps the two words apart. The mass of the bag is the amount of inertia it has, in kilograms. Its weight is the force with which the Earth pulls it, in newtons. The second law connects the two. A falling body has only its weight acting, and it accelerates at \(g\). So \(W = mg\).

Property
Mass
Weight
What it is
The measure of a body's inertia.
The gravitational pull on the body.
Kind of quantity
Scalar.
Vector, pointing down.
SI unit
kilogram, kg.
newton, N.
On the Moon
Unchanged.
About one-sixth, since \(g_{\text{Moon}} \approx 1.6\,\text{m/s}^2\).
Measured by
A pan balance, comparing with standard masses.
A spring balance, which reads the pull.

An astronaut of mass \(60\,\text{kg}\) weighs \(600\,\text{N}\) on the Earth. On the Moon her mass is still \(60\,\text{kg}\), and a push that gave her \(1\,\text{m/s}^2\) on the Earth gives her \(1\,\text{m/s}^2\) there too. But her weight on the Moon is only \(60 \times 1.6 = 96\,\text{N}\), so she can jump much higher.

CheckpointUnanswered

A box of mass \(10\,\text{kg}\) is taken to the Moon, where \(g = 1.6\,\text{m/s}^2\). Which statement is correct?

Now the trolleys at the station. One porter's push on the loaded trolley gives a small acceleration, because the mass is large. Two porters give twice the net force to the same mass, and so twice the acceleration. If the empty trolley has half the mass of the loaded one, two porters on the loaded trolley match one porter on the empty trolley exactly, as Fig 3.1 showed.

Story · Isaac Newton, Principia, 1687
Three laws on one page

Edmond Halley visited Newton in Cambridge in 1684 and asked him about the path of a planet. Newton had the answer but not the paper. Over the next three years he wrote the Philosophiae Naturalis Principia Mathematica, which Halley paid to publish in 1687. Near the start of it stand three short "axioms, or laws of motion". The second, in Newton's words, says that the change of motion is proportional to the motive force impressed.

Exam traps
  1. Using one force, such as the engine's push, in F = ma.
    The second law uses the net force, the vector sum of all the forces on the body.
  2. Assuming the acceleration is along the velocity.
    The acceleration is along the net force. A rising stone moves up and accelerates down.
  3. Giving weight in kilograms.
    Weight is a force, in newtons: \(W = mg\). Kilograms measure mass.