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Objects in Equilibrium · Lesson 1 of 6

The Condition for Equilibrium

14 min read2 ideas7 checks2 figures to playBy Asheshanand Acharya
What you will learn 0 / 2
Sum of forces is zero
Maths you need
Look around
The lamp on the platform

Stand on any railway platform in India and look up. A lamp hangs from the roof by a chain. The lamp does not move all day. Yet the Earth pulls the lamp down every second, and the chain pulls the lamp up every second. Two forces act, and nothing happens. The question of this lesson is simple: when do forces produce nothing?

you will be able to name every force on a body at rest, draw those forces on one diagram, and show that they cancel.

Forces that cancel

The lamp does not move because the two forces on the lamp cancel. The Earth pulls the lamp down with its weight \(W\). The chain pulls the lamp up with a tension \(T\). The two forces are equal in size and opposite in direction, so their vector sum is zero. The sum of all the forces on a body is called the net force. When the net force is zero, the forces produce no change in the motion of the body.

definition 2.1
Equilibrium

A body is in equilibrium when the net force on the body is zero. For a body at rest, equilibrium means that the body stays at rest. This state is called static equilibrium, and it is the only kind of equilibrium in this chapter.

RememberThe condition for equilibrium
\[ \sum \vec F = 0 \quad\Longleftrightarrow\quad \sum F_x = 0 \ \text{and}\ \sum F_y = 0 \]
Holds whenFor a body treated as a particle, with all the forces in one plane. The axes \(x\) and \(y\) may be any two perpendicular directions in that plane.
Symbols\(\vec F\) each force on the body; \(F_x\), \(F_y\) the components of each force along the chosen axes.
Unitsnewton (N) for every force and every component.

One vector equation, two number equations

A vector is zero only when every component of the vector is zero. So the single vector equation \(\sum \vec F = 0\) becomes two ordinary equations, one for each axis. The forces along \(x\) must cancel among themselves. The forces along \(y\) must also cancel among themselves. Two equations can find two unknowns, for example two tensions, or one tension and one normal force.

What the condition does not say

The condition \(\sum \vec F = 0\) is short, and students read too much into it. Four statements are often believed and are false.

  • It does not say that no force acts. The lamp has two forces on it, and a book on a table has two.
  • It does not say that the forces are small. A bridge cable may carry a tension of a million newtons and still be in equilibrium.
  • It does not say that a body at rest for an instant is in equilibrium. A ball thrown up stops at the top for an instant. But the only force on it is its weight, so the net force is not zero.
  • It does not say that the body cannot turn. Two equal and opposite forces along different lines can rotate a body. In this chapter every body is a particle, so all forces act at one point and turning does not arise.
Common mistake

"At rest" and "in equilibrium" are not the same statement. A body in equilibrium stays at rest. A ball at the top of its flight is at rest only for an instant. It has a net force on it and does not stay at rest. Always test the forces, never only the velocity.

Deeper

A body that moves with constant velocity also has zero net force on it, so it is also in equilibrium. A Metro coach cruising at a steady speed on a straight track is an example. This chapter deals only with bodies at rest; motion with forces is the subject of the next chapter.

CheckpointUnanswered

A cricket ball is thrown straight up. At the highest point, the ball is at rest for an instant. Is the ball in equilibrium at that instant?

Checkpoint · select all that applyUnanswered

A signboard hangs at rest from two chains. Which statements are certainly true?

Free body diagram and force polygon
Maths you need

The free-body diagram, again

The condition \(\sum \vec F = 0\) needs a list of every force on one chosen body. You learned to draw that list in the last chapter, as a free-body diagram. The body is drawn alone, with one arrow for each force on it. This chapter is practice. Every problem starts with the same diagram, drawn again and again, until drawing it takes no thought at all.

The method, step by step

The same five steps work for every problem in this chapter. They take a minute to learn and a month of practice to make automatic.

  1. Choose one body. Draw it alone, as a small block or a dot.
  2. Draw the weight \(W = mg\), vertically down. The weight is the only force that acts without contact.
  3. Go round the edge of the body. Every contact gives one force. A surface gives a normal force perpendicular to the surface. A string gives a tension along the string, away from the body.
  4. Check that no arrow is a force that the body exerts on something else.
  5. Choose two perpendicular axes and write \(\sum F_x = 0\) and \(\sum F_y = 0\).
Intuition

Imagine that the body is inside a closed bubble. Only two kinds of force can reach the body through the bubble. One is gravity, which needs no contact. The other is a push or pull from something that touches the bubble. Walk round the bubble with a finger and count the contacts. That count, plus one for the weight, is the number of arrows.

Forces head to tail

Draw the forces of a free-body diagram one after another, the tail of each arrow at the head of the one before. If the net force is zero, the last arrow ends exactly where the first arrow began. The arrows close into a figure called the force polygon. A closed polygon is the picture of \(\sum \vec F = 0\). For two forces the polygon is flat: the second arrow runs back along the first.

A block on a table, its free-body diagram and its force polygonA 2 kg block rests on a table. The chips cut the block free, then add its weight W of 20 N downward and the normal force N of 20 N upward. The last chip draws the two forces head to tail: the head of N returns to the tail of W, so the polygon closes. in place free body polygon m
Fig 1.1A 2 kg block on a table. Step through the chips. The body is first drawn alone. Then its weight \(W = 20\,\text{N}\) appears, then the normal force \(N\) from the table. The last chip draws \(W\) and \(N\) head to tail: \(N\) returns to the start, so the polygon closes and \(N = W = 20\,\text{N}\).
ExampleA book on a desk

A physics book of mass \(1.2\,\text{kg}\) lies at rest on a level desk. Take \(g = 10\,\text{m/s}^2\). Draw the free-body diagram of the book and find the force that the desk exerts on the book.

Try it on paper first. The solution is one tap away when you are ready.
A lamp hanging from one string, its free-body diagram and its force polygonA 3 kg lamp hangs at rest from one vertical string. The chips cut the lamp free, then add its weight W of 30 N downward and the tension T of 30 N upward along the string. The last chip draws the two forces head to tail, and the polygon closes. in place free body polygon m
Fig 1.2A 3 kg lamp hanging from one string. The lamp is drawn alone, then its weight \(W = 30\,\text{N}\), then the tension \(T\) along the string, away from the lamp. The last chip lays \(W\) and \(T\) head to tail. The polygon closes when \(T = 30\,\text{N}\).
CheckpointUnanswered

A student draws the three forces on a body head to tail. The last arrow ends a little to the right of the start of the first arrow. What does the gap mean?

Checkpoint · numericUnanswered

A lantern of mass \(1.5\,\text{kg}\) hangs at rest from a single vertical string. Take \(g = 10\,\text{m/s}^2\). Find the tension in the string, in newtons.

N± 2 %
CheckpointUnanswered

A ball hangs from a vertical string and just touches a smooth vertical wall. What force does the wall exert on the ball?

Checkpoint · in your own wordsUnanswered

Explain why the forces on a body in equilibrium, drawn head to tail, must end where they began.

EstimateUnanswered

A ceiling fan hangs at rest from its rod in a classroom. Roughly what is the pull of the rod on the fan, in newtons? Take \(g = 10\,\text{m/s}^2\).

Nrough value is enough
In the world
What a weighing machine reads

A weighing machine at a railway station does not measure mass directly. The platform of the machine pushes up on your feet with a normal force, and the machine measures that push. When you stand still, you are in equilibrium, so the push equals your weight. The dial shows the push divided by \(g\), which is your mass. Lean on a wall while you stand on the machine, and the reading falls, because the wall now shares the work of balancing your weight.

Exam traps
  1. Calling a body in equilibrium because it is at rest for an instant.
    Test the forces. In equilibrium the net force is zero. A body at rest for an instant may still have a net force on it.
  2. Drawing the force that the body exerts on the table in the free-body diagram of the body.
    Ask of every arrow, "Which body does this force act on?" If the answer is not the chosen body, remove the arrow.
  3. Forgetting the weight because nothing seems to touch the body from below.
    Draw the weight first, every time. Gravity needs no contact.