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Sound as a Longitudinal Wave

15 min read4 ideas5 checks3 figures to playBy Asheshanand Acharya
What you will learn 0 / 4
A sound begins at a vibrating source
Look around
The dhol in the procession

A Ganesh procession passes your street, and a drummer beats a large dhol. Each beat reaches you a moment after the stick lands. At close range you feel the beat in your chest as well as hear it. Yet no wind blows from the drum to you. The air of the street stays where it was.

you will see exactly what travels from the drum to your ear, and what stays behind in the air.

A sound begins with a vibration

At its core, a sound wave begins with a vibrating source. The source may be the cone of a loudspeaker, a guitar string, or your own vocal cords. The vibrations of the source nudge the particles of air next to it. Those particles nudge their neighbours in turn. So a chain of pushes and pulls ripples out through the surrounding medium.

Amplitude and frequency are independent

Amplitude and frequency

Before we go deeper into sound waves, we need two basic properties of any wave. They are the amplitude and the frequency. Each one describes the wave independently of the other.

The amplitude is the largest displacement of the particles from their equilibrium positions. In a sound wave, a larger amplitude means three things:

  • a greater pressure variation, \(\Delta P_{\text{max}}\), in the air;
  • more energy carried by the wave;
  • a louder sound heard by our ears.

Think of the amplitude as the strength of the vibration. When you turn up the volume of a speaker, you increase the amplitude of its sound wave.

The frequency is the number of complete oscillations in one second. It is measured in hertz (Hz). In a sound wave, the frequency decides the pitch that we hear:

  • a higher frequency gives a higher pitch, like a whistle;
  • a lower frequency gives a lower pitch, like a bass drum.

The amplitude and the frequency are independent properties. A sound can be loud and high, or quiet and low. The two can change separately.

Intuition

Picture a music system with two separate knobs. One knob is the volume, and it sets the amplitude. The other knob is the tone, and it sets the frequency. Turning one knob never moves the other.

Seven samples to hear

Now listen to seven samples, and notice what amplitude and frequency each do to the sound. First keep the frequency fixed at \(440\,\text{Hz}\), the musical note A4. Change only the amplitude, from quieter (\(0.5\)) to normal (\(1\)) to louder (\(2\)). The pitch stays the same, and only the loudness changes.

Next keep the amplitude fixed at \(1\) and change the frequency. The loudness stays the same, but the pitch shifts. \(220\,\text{Hz}\) (A3) sounds lower, \(440\,\text{Hz}\) (A4) is in the middle, and \(880\,\text{Hz}\) (A5) is higher. Last, combine both changes. Compare a loud, high note (\(880\,\text{Hz}\) at amplitude \(2\)) with a quiet, low note (\(220\,\text{Hz}\) at amplitude \(0.5\)).

Seven sound samples: amplitude and frequencyA graph of the displacement s of the air, in relative units from minus 2 to plus 2, against the distance x from 0 to 3.2 metres, for a sound travelling at 343 metres per second. Seven chips choose a sample: 440 hertz at amplitude 0.5, 1 and 2; 220 hertz and 880 hertz at amplitude 1; 880 hertz at amplitude 2; and 220 hertz at amplitude 0.5. The drawn wave follows the chip: its height is the amplitude, and its wavelength is 343 divided by the frequency. A readout gives the frequency, the amplitude and the wavelength. A Listen chip plays the same tone for three seconds; nothing plays until it is clicked.12−1−2Oxs λ f = 440 Hz, amplitude 0.5, λ = 0.78 m
Fig 1.1The seven samples. Choose a chip, then press Listen to hear that sample for three seconds. Nothing plays until you press Listen. The drawn wave follows the chip: its height is the relative amplitude, and \(\lambda\) is the wavelength in air at \(343\,\text{m/s}\).

The drawing in Fig 1.1 shows what you hear. A louder chip makes the wave taller but keeps its wavelength. A higher chip packs the crests closer but keeps their height. At \(343\,\text{m/s}\), the speed of sound that this lesson uses, \(440\,\text{Hz}\) has a wavelength of \(0.78\,\text{m}\). \(220\,\text{Hz}\) has \(1.56\,\text{m}\), and \(880\,\text{Hz}\) has \(0.39\,\text{m}\).

These demonstrations show clearly that amplitude and frequency are independent. Changing one does not change the other. The amplitude controls the loudness, and the frequency controls the pitch.

Amplitude and frequency vary separatelyFour small graphs of the pressure variation delta P against time t, in two rows. Top row: two traces with the same frequency, three cycles each; the left one has a small amplitude and the right one a large amplitude. Bottom row: two traces with the same amplitude; the left one has a low frequency, two cycles, and the right one a high frequency, five cycles.OtΔP small A OtΔP large A OtΔP low f OtΔP high f
Fig 1.2Amplitude and frequency of a sound wave are independent. Top row: the same frequency with a small and a large amplitude. Bottom row: the same amplitude with a low and a high frequency.
The equation and speed of a sound wave
Maths you need

The wave equation for sound

Consider a sinusoidal sound wave travelling through a medium along \(x\). The displacement \(s\) of a particle of the medium depends on its position \(x\) and on the time \(t\). We can write it as

\[ s(x, t) = s_{\text{max}}\cos(kx - \omega t) \]

or, equally well, as \(s(x, t) = s_{\text{max}}\sin(kx - \omega t)\). The two differ only by where the clock starts. In these equations:

  • \(s_{\text{max}}\) is the amplitude, the largest displacement;
  • \(k = 2\pi/\lambda\) is the wave number, where \(\lambda\) is the wavelength;
  • \(\omega = 2\pi f\) is the angular frequency, where \(f\) is the frequency in Hz;
  • \(kx - \omega t\) is the phase of the wave.
RememberThe displacement wave of sound
\[ \begin{aligned} s(x, t) &= s_{\text{max}}\cos(kx - \omega t) \\ k &= \dfrac{2\pi}{\lambda}, \quad \omega = 2\pi f \end{aligned} \]
Holds whena harmonic sound wave travelling towards \(+x\). The displacement \(s\) is along the direction of travel.
Symbols\(s\) displacement of a particle from its mean position, \(s_{\text{max}}\) amplitude, \(k\) wave number, \(\omega\) angular frequency, \(\lambda\) wavelength, \(f\) frequency
Units\(s\) in m, \(k\) in rad/m, \(\omega\) in rad/s, \(\lambda\) in m, \(f\) in Hz

The speed of the wave

Sound waves obey the same relation between speed, wavelength and frequency as waves on a string. The wave speed \(v\) can be written in several equal ways:

\[ v = \frac{\lambda}{T} = \lambda f = \frac{\omega}{k} \]

Here \(T = 1/f\) is the period, the time for one complete oscillation. These relations hold for every travelling wave. What matters for sound is this: the speed \(v\) depends on the properties of the medium. It does not depend on the frequency or the amplitude of the wave. Lesson 3 explores this.

RememberSpeed, wavelength and frequency
\[ v = \dfrac{\lambda}{T} = \lambda f = \dfrac{\omega}{k} \]
Holds whenevery travelling wave, sound included. For sound, \(v\) is fixed by the medium.
Symbols\(v\) wave speed, \(\lambda\) wavelength, \(T\) period, \(f\) frequency, \(\omega\) angular frequency, \(k\) wave number
Units\(v\) in m/s, \(\lambda\) in m, \(T\) in s, \(f\) in Hz
CheckpointUnanswered

If you double the amplitude of a sound wave, what happens to its frequency?

CheckpointUnanswered

A sound wave has a wavelength \(\lambda = 0.5\,\text{m}\) and a frequency \(f = 686\,\text{Hz}\). What is its speed?

Checkpoint · numericUnanswered

The note A5 has a frequency of \(880\,\text{Hz}\). Take the speed of sound as \(343\,\text{m/s}\). What is its wavelength in air, in metres?

m± 2 %
Compressions and rarefactions travel

Compressions and rarefactions

The disturbance moves outward as a longitudinal wave. The particles oscillate parallel to the direction in which the wave advances. As they do so, the medium alternates between two kinds of region. In some regions the particles are squeezed together; these are compressions. In others they are spread apart; these are rarefactions.

In a compression, the particles are crowded together. The local pressure and the local density are higher than average. In a rarefaction, the particles are pulled apart. The local pressure and the local density are lower than average. Fig 1.3 shows both.

A piston generating a sound wave in a tubeA horizontal tube of air with a piston at its left end. The air is drawn as four rows of particles, and one column is painted. When played, the piston moves back and forth. Each push crowds the air next to it into a compression, and each pull leaves a rarefaction. The compressions travel to the right along the tube, marked v, and a label rides with one of them. The painted column only swings to and fro over a short dashed line below the tube and never travels along it. A Listen chip plays a 440 hertz tone; nothing plays until it is clicked. The drawing is slowed: here one oscillation takes 2 seconds. one particle piston compression v
Fig 1.3A vibrating piston generates a sound wave in a tube of air. Press play. The piston pushes and pulls the air next to it, and each compression it forms travels to the right at the speed \(v\). Every particle only oscillates about its own mean position. The drawing is slowed; the Listen chip plays the real \(440\,\text{Hz}\) tone, and only when pressed.

Watch the painted column in Fig 1.3. It swings to and fro over its short dashed line and never leaves it. The compressions, however, march steadily down the tube. The particles here move as \(s = s_{\text{max}}\sin(\omega t - kx)\), an equation of the same type as the one above.

It is this rhythmic journey of compressions and rarefactions that travels through the air, or any other medium, and reaches our ears as sound. Whenever you hear a sound, you hear the oscillation of the particles of the medium. That oscillation shows itself as a variation of pressure at your ear. The Listen chip of Fig 1.3 plays a sound wave of \(440\,\text{Hz}\).

CheckpointUnanswered

True or false? In a sound wave travelling through air, the air molecules themselves travel from the source to your ear.

CheckpointUnanswered

In a compression region of a sound wave, the air pressure is

Story · Robert Boyle, 1660
A watch in an empty jar

In 1660 Robert Boyle hung a ticking watch inside a glass jar and pumped the air out with his new air pump. As the air thinned, the ticking grew fainter until it could hardly be heard. When he let the air back in, the ticking returned. Boyle concluded that air carries sound to the ear. There must be particles to push and pull, or the vibration of the watch has nothing to pass along.

Now return to the dhol. The stick sets the skin of the drum vibrating. The skin pushes and pulls the air beside it, and compressions and rarefactions travel out to you at the speed of sound. Each layer of air only swings about its own place, so no wind blows. What reaches your ear, and your chest, is the travelling variation of pressure.

Exam traps
  1. Thinking that a louder sound has a higher pitch.
    Loudness follows the amplitude and pitch follows the frequency. The two are independent.
  2. Thinking that the air travels from the source to the ear.
    Only the pattern of compressions and rarefactions travels. Each particle oscillates about its own mean position.
  3. Using \(v = f/\lambda\) or forgetting the wavelength.
    The speed is \(v = \lambda f\). Check the units: \(\text{m} \times \text{Hz} = \text{m/s}\).