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Electromagnetic Waves

15 min read3 ideas7 checks2 figures to playBy Asheshanand Acharya
What you will learn 0 / 3
How a changing field makes a wave

Fields that keep each other going

Faraday's law says that a changing magnetic field makes an electric field. The Ampere-Maxwell law says that a changing electric field makes a magnetic field. Suppose an electric field somewhere starts to change. It makes a changing magnetic field around it. That changing magnetic field makes a changing electric field a little further out, and so on. The disturbance spreads outward on its own, with no charge and no medium needed.

Such a travelling pair of fields is an electromagnetic wave. What starts one? A charge at rest has only a steady electric field. A charge moving at a steady velocity carries its fields along with it, and sends nothing away. A charge that accelerates changes its fields suddenly, and that change travels outward as a wave. So accelerated charges radiate.

The antenna

An antenna is a conductor in which charges are driven up and down. Join a straight rod to an alternating source, and charge surges to its top, then to its bottom, \(f\) times each second. The charges accelerate all the time, so the rod radiates. Its fields change \(f\) times each second, so the wave it sends out has the frequency \(f\) of the source.

An antenna sends out waves at its own frequencyA vertical antenna is driven by an alternating source. The charges at its two ends swap sign every half cycle, and each cycle sends one crest of the wave outward. Press play. At 100 megahertz the crests are 3 metres apart. The second chip doubles the frequency: the crests are then 1.5 metres apart, and they move out at the same speed, c. λ f = 100 MHz, λ = c/f = 3.0 m
Fig 4.1A vertical antenna driven at \(100\,\text{MHz}\). Press play. Each cycle of the charges at its ends sends out one crest, and the crests are \(3\,\text{m}\) apart. Choose \(200\,\text{MHz}\): the crests come twice as often and are \(1.5\,\text{m}\) apart, moving out at the same speed.

In the figure above the crests always move out at the same speed, \(c = 3\times10^8\,\text{m/s}\). One crest leaves in each period \(1/f\), so the crests are \(\lambda = c/f\) apart. At \(100\,\text{MHz}\) that is \(3\,\text{m}\), and at \(200\,\text{MHz}\) it is \(1.5\,\text{m}\). An antenna works best when its length is about half a wavelength, so an antenna for \(100\,\text{MHz}\) is about \(1.5\,\text{m}\) long.

CheckpointUnanswered

Which of these charges sends out no electromagnetic wave?

The plane wave e and b in step
Maths you need

The plane wave

Far from the antenna, a small part of the spreading wave is nearly flat. It is a plane wave. Let it travel along \(x\). Its electric field points along \(y\) and its magnetic field along \(z\). Both are travelling waves of the form met in the chapter Introduction to Waves.

\[ \begin{gathered} E_y = E_0\sin(kx - \omega t) \\ B_z = B_0\sin(kx - \omega t) \end{gathered} \]

Here \(k = 2\pi/\lambda\) and \(\omega = 2\pi f\), and the wave travels at \(\omega/k = c\).

E and B advance togetherA plane electromagnetic wave travels along x. The electric field, in teal, points up and down the page along y; the magnetic field, in violet, points along z, drawn slanting towards the reader. Both come from the same sine, so they reach their peaks together and pass through zero together. Press play: the pattern moves along x, the direction of E cross B. The readout gives E and B at x = 6 metres; B is always E divided by c. The chips set the amplitude of E at 300 or 600 volts per metre.EBE × B y z at x = 6 m: E = 0 V/m, B = 0.00 μT
Fig 4.2A plane electromagnetic wave travelling along \(x\). \(\vec E\), in teal, points along \(y\); \(\vec B\), in violet, points along \(z\), drawn slanting towards you. Press play: the two fields peak together, and the pattern moves along \(\vec E\times\vec B\). The readout gives both fields at \(x = 6\,\text{m}\).

Watch the figure above. The two fields rise and fall together, in phase, at every point. They are at right angles to each other. Both are at right angles to the direction of travel, so the wave is a transverse wave. The wave moves along \(\vec E\times\vec B\). Here \(\hat j\times\hat k = \hat i\), so it moves along \(+x\).

law 16.2
The electromagnetic wave

In a plane electromagnetic wave in vacuum, \(\vec E\) and \(\vec B\) oscillate in phase, at right angles to each other and to the direction of travel. The wave travels along \(\vec E\times\vec B\) at the speed \(c\), and the amplitudes obey \(E_0 = cB_0\).

Why \(E_0 = cB_0\)

The two amplitudes are not free. Faraday's law ties them together. Take a thin rectangle in the plane of \(\vec E\), of width \(dx\) along the travel. The electric field is a little different on its two long sides. The difference gives a circulation of \(\vec E\), which must equal minus the rate of change of the magnetic flux through the rectangle. For the plane wave this reads \(\partial E/\partial x = -\partial B/\partial t\).

Deriving \(\dfrac{E_0}{B_0} = c\) fill the gap
1

\[ \dfrac{\partial E}{\partial x} = -\dfrac{\partial B}{\partial t} \]

Why. Faraday's law for a thin rectangle in the plane of \(\vec E\). Write \(\theta = kx - \omega t\) for the phase.

2

?

Your turn. differentiate \(E = E_0\sin\theta\) with respect to \(x\), and \(B = B_0\sin\theta\) with respect to \(t\). Which line is it?

3

\[ kE_0 = \omega B_0 \]

Why. the two cosines are equal at every \(x\) and \(t\), so they cancel.

4

\[ \dfrac{E_0}{B_0} = \dfrac{\omega}{k} = c \]

Read it. \(\omega/k\) is the speed of the wave.

Which line fills step 2?Unanswered
RememberAmplitudes of an electromagnetic wave
\[ \begin{gathered} E_0 = cB_0 \\ E = cB \end{gathered} \]
Holds whena plane electromagnetic wave in vacuum, at every point and every instant, since \(\vec E\) and \(\vec B\) are in phase.
Symbols\(E_0\), \(B_0\) the amplitudes of the electric and magnetic fields, \(c\) the speed of light
Units\(E\) in V/m, \(B\) in T, \(c = 3\times10^8\,\text{m/s}\)

So an electric field of \(300\,\text{V/m}\) goes with a magnetic field of only \(300/(3\times10^8) = 10^{-6}\,\text{T}\), one microtesla. In tesla the magnetic field of light is tiny. The force \(qvB\) it exerts on a charge is \(v/c\) times the electric force \(qE\). For slow charges the electric field does almost all the pushing.

ExampleReading a wave from its equation

The electric field of an electromagnetic wave is \(E_y = 60\sin(0.5x - 1.5\times10^8t)\,\text{V/m}\), with \(x\) in metres and \(t\) in seconds. Find its wavelength, frequency and speed, and the amplitude and direction of \(\vec B\).

Try it on paper first. The solution is one tap away when you are ready.
CheckpointUnanswered

At some instant the electric field of a wave points along \(+z\) and its magnetic field along \(+x\). In which direction does the wave travel?

CheckpointUnanswered

What is the phase difference between the electric and magnetic fields of a plane electromagnetic wave in vacuum?

Checkpoint · numericUnanswered

A wave has \(E_z = 20\sin(2x - 6\times10^8t)\,\text{V/m}\), with \(x\) in metres and \(t\) in seconds. What is its frequency, in megahertz?

MHz± 2 %
Checkpoint · numericUnanswered

The electric field of a radio wave has an amplitude of \(150\,\text{V/m}\). What is the amplitude of its magnetic field, in microtesla?

μT± 2 %
The speed of light from mu0 and epsilon0
Maths you need

The speed of light from two constants

Maxwell's equations give the speed of the wave from the two constants of electricity and magnetism. It is \(1/\sqrt{\mu_0\epsilon_0}\). Here \(\mu_0\epsilon_0\) \(= 4\pi\times10^{-7}\times8.85\times10^{-12}\) \(= 1.11\times10^{-17}\,\text{s}^2/\text{m}^2\). So the speed is \(1/\sqrt{1.11\times10^{-17}}\) \(= 3.0\times10^8\,\text{m/s}\), the speed of light.

RememberSpeed of an electromagnetic wave
\[ \begin{gathered} c = \dfrac{1}{\sqrt{\mu_0\epsilon_0}} \\ v = \dfrac{c}{\sqrt{\mu_r\epsilon_r}} \end{gathered} \]
Holds when\(c\) in vacuum, for every frequency; \(v\) in a uniform medium of relative permeability \(\mu_r\) and relative permittivity \(\epsilon_r\), both taken at the frequency of the wave.
Symbols\(\mu_0\) permeability and \(\epsilon_0\) permittivity of free space, \(\mu_r\), \(\epsilon_r\) their relative values in the medium
Units\(c\), \(v\) in m/s

Every electromagnetic wave in vacuum, of any frequency, travels at this one speed. Radio waves, light and X-rays differ only in frequency and wavelength. In a material the constants become \(\mu = \mu_r\mu_0\) and \(\epsilon = \epsilon_r\epsilon_0\), so the wave slows to \(v = c/\sqrt{\mu_r\epsilon_r}\). The refractive index of the chapter Refraction, Total Internal Reflection and Prisms is then \(n = c/v = \sqrt{\mu_r\epsilon_r}\).

For glass, \(\mu_r = 1\) and \(\epsilon_r = 2.25\) at the frequency of light. So \(v = 3\times10^8/\sqrt{2.25} = 2\times10^8\,\text{m/s}\) and \(n = 1.5\). Maxwell's constants explain the bending of light in a lens.

Common mistake

Use \(\epsilon_r\) at the frequency of the wave. Water has \(\epsilon_r\) about \(80\) in a steady field, which would give \(n\) near \(9\). For light it is about \(1.77\), and \(n = 1.33\). The molecules of water can turn to follow a slow field, but not a field that reverses about \(10^{15}\) times a second.

Checkpoint · numericUnanswered

A plastic has \(\epsilon_r = 2.56\) and \(\mu_r = 1\) at the frequency of light. What is the speed of light in it, in units of \(10^8\,\text{m/s}\)?

± 2 %
Story · Heinrich Hertz, 1887
Sparks across a room

Heinrich Hertz, a young professor at Karlsruhe in Germany, set out to test Maxwell's waves. He made sparks jump across a small gap fed by an induction coil. A few metres away, a loop of wire with a tiny gap of its own sparked too, though nothing joined the two. The sparks were carried by electromagnetic waves. Hertz showed that the waves reflect, refract and form standing waves. Their speed came out close to the speed of light, as Maxwell had predicted. The unit of frequency, the hertz, carries his name.

Exam traps
  1. Thinking any moving charge radiates.
    Only an accelerated charge radiates; a steady current or a charge at constant velocity does not.
  2. Taking the travel along \(\vec B\times\vec E\).
    The wave travels along \(\vec E\times\vec B\); the order matters.
  3. Putting a phase difference between \(E\) and \(B\).
    In a plane wave in vacuum they are in phase, and \(E = cB\) at every point.
  4. Using a slow-field \(\epsilon_r\) for light.
    Take \(\epsilon_r\) at the frequency of the wave.