Fields that keep each other going
Faraday's law says that a changing magnetic field makes an electric field. The Ampere-Maxwell law says that a changing electric field makes a magnetic field. Suppose an electric field somewhere starts to change. It makes a changing magnetic field around it. That changing magnetic field makes a changing electric field a little further out, and so on. The disturbance spreads outward on its own, with no charge and no medium needed.
Such a travelling pair of fields is an electromagnetic wave. What starts one? A charge at rest has only a steady electric field. A charge moving at a steady velocity carries its fields along with it, and sends nothing away. A charge that accelerates changes its fields suddenly, and that change travels outward as a wave. So accelerated charges radiate.
The antenna
An antenna is a conductor in which charges are driven up and down. Join a straight rod to an alternating source, and charge surges to its top, then to its bottom, \(f\) times each second. The charges accelerate all the time, so the rod radiates. Its fields change \(f\) times each second, so the wave it sends out has the frequency \(f\) of the source.
In the figure above the crests always move out at the same speed, \(c = 3\times10^8\,\text{m/s}\). One crest leaves in each period \(1/f\), so the crests are \(\lambda = c/f\) apart. At \(100\,\text{MHz}\) that is \(3\,\text{m}\), and at \(200\,\text{MHz}\) it is \(1.5\,\text{m}\). An antenna works best when its length is about half a wavelength, so an antenna for \(100\,\text{MHz}\) is about \(1.5\,\text{m}\) long.
Which of these charges sends out no electromagnetic wave?
The plane wave
Far from the antenna, a small part of the spreading wave is nearly flat. It is a plane wave. Let it travel along \(x\). Its electric field points along \(y\) and its magnetic field along \(z\). Both are travelling waves of the form met in the chapter Introduction to Waves.
\[ \begin{gathered} E_y = E_0\sin(kx - \omega t) \\ B_z = B_0\sin(kx - \omega t) \end{gathered} \]
Here \(k = 2\pi/\lambda\) and \(\omega = 2\pi f\), and the wave travels at \(\omega/k = c\).
Watch the figure above. The two fields rise and fall together, in phase, at every point. They are at right angles to each other. Both are at right angles to the direction of travel, so the wave is a transverse wave. The wave moves along \(\vec E\times\vec B\). Here \(\hat j\times\hat k = \hat i\), so it moves along \(+x\).
In a plane electromagnetic wave in vacuum, \(\vec E\) and \(\vec B\) oscillate in phase, at right angles to each other and to the direction of travel. The wave travels along \(\vec E\times\vec B\) at the speed \(c\), and the amplitudes obey \(E_0 = cB_0\).
Why \(E_0 = cB_0\)
The two amplitudes are not free. Faraday's law ties them together. Take a thin rectangle in the plane of \(\vec E\), of width \(dx\) along the travel. The electric field is a little different on its two long sides. The difference gives a circulation of \(\vec E\), which must equal minus the rate of change of the magnetic flux through the rectangle. For the plane wave this reads \(\partial E/\partial x = -\partial B/\partial t\).
\[ \dfrac{\partial E}{\partial x} = -\dfrac{\partial B}{\partial t} \]
Why. Faraday's law for a thin rectangle in the plane of \(\vec E\). Write \(\theta = kx - \omega t\) for the phase.
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Your turn. differentiate \(E = E_0\sin\theta\) with respect to \(x\), and \(B = B_0\sin\theta\) with respect to \(t\). Which line is it?
\[ kE_0 = \omega B_0 \]
Why. the two cosines are equal at every \(x\) and \(t\), so they cancel.
\[ \dfrac{E_0}{B_0} = \dfrac{\omega}{k} = c \]
Read it. \(\omega/k\) is the speed of the wave.
So an electric field of \(300\,\text{V/m}\) goes with a magnetic field of only \(300/(3\times10^8) = 10^{-6}\,\text{T}\), one microtesla. In tesla the magnetic field of light is tiny. The force \(qvB\) it exerts on a charge is \(v/c\) times the electric force \(qE\). For slow charges the electric field does almost all the pushing.
The electric field of an electromagnetic wave is \(E_y = 60\sin(0.5x - 1.5\times10^8t)\,\text{V/m}\), with \(x\) in metres and \(t\) in seconds. Find its wavelength, frequency and speed, and the amplitude and direction of \(\vec B\).
(a) \(k = 0.5\,\text{rad/m}\), so \(\lambda = 2\pi/k = 4\pi = 12.6\,\text{m}\).
(b) \(\omega = 1.5\times10^8\,\text{rad/s}\), so \(f = \omega/2\pi = 2.4\times10^7\,\text{Hz}\).
(c) \(v = \omega/k\) \(= 1.5\times10^8/0.5 = 3\times10^8\,\text{m/s}\), the speed of light.
(d) \(B_0 = E_0/c\) \(= 60/(3\times10^8) = 2\times10^{-7}\,\text{T}\). The wave runs along \(+x\) with \(\vec E\) along \(y\), so \(\vec B\) is along \(z\), since \(\hat j\times\hat k = \hat i\).
Values used: \(c = 3\times10^8\,\text{m/s}\).
At some instant the electric field of a wave points along \(+z\) and its magnetic field along \(+x\). In which direction does the wave travel?
What is the phase difference between the electric and magnetic fields of a plane electromagnetic wave in vacuum?
A wave has \(E_z = 20\sin(2x - 6\times10^8t)\,\text{V/m}\), with \(x\) in metres and \(t\) in seconds. What is its frequency, in megahertz?
The electric field of a radio wave has an amplitude of \(150\,\text{V/m}\). What is the amplitude of its magnetic field, in microtesla?
The speed of light from two constants
Maxwell's equations give the speed of the wave from the two constants of electricity and magnetism. It is \(1/\sqrt{\mu_0\epsilon_0}\). Here \(\mu_0\epsilon_0\) \(= 4\pi\times10^{-7}\times8.85\times10^{-12}\) \(= 1.11\times10^{-17}\,\text{s}^2/\text{m}^2\). So the speed is \(1/\sqrt{1.11\times10^{-17}}\) \(= 3.0\times10^8\,\text{m/s}\), the speed of light.
Every electromagnetic wave in vacuum, of any frequency, travels at this one speed. Radio waves, light and X-rays differ only in frequency and wavelength. In a material the constants become \(\mu = \mu_r\mu_0\) and \(\epsilon = \epsilon_r\epsilon_0\), so the wave slows to \(v = c/\sqrt{\mu_r\epsilon_r}\). The refractive index of the chapter Refraction, Total Internal Reflection and Prisms is then \(n = c/v = \sqrt{\mu_r\epsilon_r}\).
For glass, \(\mu_r = 1\) and \(\epsilon_r = 2.25\) at the frequency of light. So \(v = 3\times10^8/\sqrt{2.25} = 2\times10^8\,\text{m/s}\) and \(n = 1.5\). Maxwell's constants explain the bending of light in a lens.
Use \(\epsilon_r\) at the frequency of the wave. Water has \(\epsilon_r\) about \(80\) in a steady field, which would give \(n\) near \(9\). For light it is about \(1.77\), and \(n = 1.33\). The molecules of water can turn to follow a slow field, but not a field that reverses about \(10^{15}\) times a second.
A plastic has \(\epsilon_r = 2.56\) and \(\mu_r = 1\) at the frequency of light. What is the speed of light in it, in units of \(10^8\,\text{m/s}\)?
Heinrich Hertz, a young professor at Karlsruhe in Germany, set out to test Maxwell's waves. He made sparks jump across a small gap fed by an induction coil. A few metres away, a loop of wire with a tiny gap of its own sparked too, though nothing joined the two. The sparks were carried by electromagnetic waves. Hertz showed that the waves reflect, refract and form standing waves. Their speed came out close to the speed of light, as Maxwell had predicted. The unit of frequency, the hertz, carries his name.
- Thinking any moving charge radiates.Only an accelerated charge radiates; a steady current or a charge at constant velocity does not.
- Taking the travel along \(\vec B\times\vec E\).The wave travels along \(\vec E\times\vec B\); the order matters.
- Putting a phase difference between \(E\) and \(B\).In a plane wave in vacuum they are in phase, and \(E = cB\) at every point.
- Using a slow-field \(\epsilon_r\) for light.Take \(\epsilon_r\) at the frequency of the wave.