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Questions on Optical Instruments and the Eye, the kind your examinations ask. Solve one on paper. Then tell the book how it went. The book believes you, and it uses your answer to plan your revision.

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Microscopes, Telescopes and Defects of Vision

24 questions · after Lesson 5, Telescopes

Simple microscope

Q1
Define the magnifying power of a microscope. Why is it defined with angles rather than sizes? Take \(D = 25\) cm throughout.
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Q2
A simple microscope has \(f = 5\) cm. Find its magnifying power when the image is at \(D\) and when it is at infinity.
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Q3
The image \(I\) is formed at \(D = 25\) cm.
  1. Find the object distance.
  2. Why must the object lie inside \(f\)?
A simple microscope: a convex lens of focal length 5 cm with the object inside the focus and a virtual magnified image at 25 cm
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Q4
Why does a shorter focal length give a larger magnifying power? Why can the magnification of a simple microscope not be made very large?
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Q5
A watchmaker's eyepiece has \(f = 2.5\) cm. Find its magnifying power for the image at \(D\) and for the relaxed eye.
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Compound microscope

Q6
The object is \(1.1\) cm from the objective and the final image is at \(D\).
  1. Find the position and magnification of the intermediate image \(I_1\).
  2. Find the magnifying power of the eyepiece and of the microscope.
  3. Find the tube length \(L\).
A compound microscope with objective of focal length 1 cm and eyepiece of focal length 5 cm, a real intermediate image and the final image at D
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Q7
Why is the objective of a compound microscope given a very short focal length, and the eyepiece a moderate one?
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Q8
The objective of a microscope magnifies \(20\) times and the eyepiece acts as a simple microscope of power \(6\). Find the total magnification.
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Q9
A microscope has \(f_o = 1\) cm and \(f_e = 4\) cm, with the lenses \(15\) cm apart and the final image at infinity. Find the object distance and the magnifying power.
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Q10
In a compound microscope, why is the intermediate image real while the final image is virtual?
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Q11
For the microscope of Q6, find the magnifying power when the final image is at infinity, and the new tube length.
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Telescopes

Q12
Write the magnifying power and the length of an astronomical telescope in normal adjustment. Find both for \(f_o = 100\) cm and \(f_e = 5\) cm.
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Q13
The telescope is in normal adjustment.
  1. Why do the foci of the two lenses coincide?
  2. Why is the objective made with a large aperture?
An astronomical telescope in normal adjustment with objective of 100 cm and eyepiece of 5 cm; parallel rays enter and leave
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Q14
The telescope of Q12 is adjusted so that the final image is at \(D\). Find the magnifying power and the length now.
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Q15
A terrestrial telescope uses an erecting lens of \(f = 5\) cm between the objective and eyepiece of Q12. Find its length in normal adjustment. Why is the erecting lens needed?
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Q16
Give three advantages of a reflecting telescope over a refracting one.
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Q17
The Moon subtends \(0.5^\circ\) at the eye. What angle does its image subtend through the telescope of Q12? Is the image erect or inverted?
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Q18
Trace the path of light in the Cassegrain telescope and name the parts.
A Cassegrain reflecting telescope: a concave primary mirror with a central hole and a small convex secondary mirror
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Defects of vision

Q19
The far point of the eye is \(2\) m.
  1. Where do parallel rays focus, and why can the eye not see distant objects clearly?
  2. Find the focal length and power of the correcting lens.
A myopic eye whose far point is 2 m; parallel rays focus in front of the retina; a lens is to correct it
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Q20
A person cannot see clearly nearer than \(50\) cm. Find the focal length and power of the lens that lets them read at \(25\) cm. Name the defect.
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Q21
What is presbyopia? Why does it develop with age, and how is it corrected?
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Q22
What is astigmatism? What kind of lens corrects it?
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Q23
A myopic person has far point \(50\) cm and near point \(12\) cm. Find the power of the lens for distant vision. With this lens, what is the nearest distance of clear vision?
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Q24
A hypermetropic eye has its near point at \(N\) (in cm). Show that a lens of focal length \(f = \frac{25N}{N - 25}\) brings the near point to \(25\) cm.
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