doPhysics.in
All chapters

Light as a Wave: Huygens' Principle

15 min read4 ideas6 checks3 figures to playBy Asheshanand Acharya
What you will learn 0 / 4
Light is a wave
Look around
Ripples from a pebble in the village pond

Drop a pebble into a still village pond. Circles of ripples spread out from the splash, each a little larger than the one before. A ripple that reaches a floating leaf sets it bobbing, and the leaf sends out small ripples of its own. Far from the splash, a short piece of a large ripple looks almost straight. Where the ripples cross into shallow water near the bank, they slow down and turn.

you will find out how each ripple builds the next one, and why the same rule bends light at the surface of glass.

Rays are not the whole story

The chapters on ray optics treated light as rays that travel in straight lines. Rays explain shadows, mirrors, lenses and prisms very well. They cannot explain everything. Light that passes through two narrow slits falls on a screen in bands of brightness and darkness. Two rays can only add light to light; they can never add up to darkness. Waves can.

For a century the question was open. In 1678 Christiaan Huygens argued that light is a wave. In his book Opticks of 1704, Isaac Newton argued that light is a stream of tiny particles. Newton's fame kept the particle picture in favour until Thomas Young's experiments with two slits, between 1801 and 1803. That experiment is the subject of the fourth lesson of this chapter.

What kind of wave?

Light is a transverse wave, like a wave on a string, but no material moves. It is an electromagnetic wave: an electric field and a magnetic field that vary together. The two fields point at right angles to each other and to the direction of travel. The unit on Electromagnetism shows how such a wave arises. This chapter needs only two facts about it.

First, the electric field does the work. It is the electric field that acts on the retina of the eye and on the sensor of a phone camera. Second, the wave has a wavelength \(\lambda\), a frequency \(f\) and a phase, like the waves of the chapters on waves. Visible light runs from about \(400\,\text{nm}\), violet, to about \(700\,\text{nm}\), red. In vacuum, and almost exactly in air, every colour travels at \(c = 3 \times 10^8\,\text{m/s}\).

With \(c = f\lambda\), yellow-orange light of \(600\,\text{nm}\) has a frequency of \(3 \times 10^8 / (600 \times 10^{-9})\) \(= 5 \times 10^{14}\,\text{Hz}\). The eye cannot follow anything that fast. It sees only the average brightness, the intensity, which grows as the square of the amplitude of the electric field. That fact will matter in every lesson that follows.

Checkpoint · numericUnanswered

Light of wavelength \(600\,\text{nm}\) travels in air. What is its frequency, in units of \(10^{14}\,\text{Hz}\)? Take \(c = 3 \times 10^8\,\text{m/s}\).

× 10¹⁴ Hz± 2 %
Wavefronts and rays

Wavefronts

Every point on one ripple of the pond is at the same stage of its up-and-down motion, all on a crest. A surface on which the wave has the same phase at every point is a wavefront. On the pond the wavefronts are circles. For light, which spreads in three dimensions, the wavefronts are surfaces.

definition 5.1
Wavefront

A wavefront is the surface through all the points that a wave, starting from its source, reaches in the same time. All these points vibrate in the same phase. Successive wavefronts one wavelength apart carry the same phase.

The shape of the wavefronts depends on the source:

  • A point source, such as a tiny bulb, sends out spherical wavefronts centred on it.
  • A line source, such as a long lit slit or a nearby tube light, sends out cylindrical wavefronts about the line.
  • A very distant source, such as the Sun or a star, gives plane wavefronts. A small piece of a sphere of enormous radius is flat.

A wave travels at right angles to its wavefronts. A ray is a line drawn along that direction, normal to the wavefronts at every point. Spherical wavefronts go with rays that spread out from the source. Plane wavefronts go with parallel rays. So ray optics and wave optics describe the same light. The ray tells where the light goes; the wavefront shows how its phase is laid out.

Checkpoint · select all that applyUnanswered

Which of these pairs of a source and the shape of its wavefronts are correct?

Huygens principle

Huygens' construction

Huygens asked a sharp question. If you know a wavefront now, how do you find it a moment later? His answer used the leaf on the pond. A disturbance that reaches any point makes that point a new source. So every point on a wavefront sends out small waves of its own, called secondary wavelets.

principle 5.1
Huygens' principle

A wavefront builds the next one in three steps:

In a time \(t\), each wavelet grows to a sphere of radius \(vt\), where \(v\) is the speed of light in the medium. Fig 1.1 shows the construction for the two commonest shapes. Play it with each chip.

Huygens' wavelets build the next wavefrontSeven points on a wavefront are marked. When played, each point sends out a secondary wavelet, drawn as a dashed half circle that grows with time. The line or arc that touches all the wavelets on their forward side is the new wavefront, drawn in colour. Two rays cross the fronts at right angles. Chips choose a plane wavefront from a distant source, where the new front is a parallel plane, or a spherical wavefront from a point source S, where the new front is a larger sphere about S. S old wavefront new wavefront
Fig 1.1Press play. Every marked point of the old wavefront sends out a dashed wavelet, and the coloured front is the envelope that touches all of them. A plane front moves forward as a parallel plane. A spherical front from S grows into a larger sphere about S. The rays stay at right angles to the fronts.

In the plane chip of Fig 1.1, all the wavelets have the same radius, so their envelope is a plane a distance \(vt\) ahead. In the spherical chip, the wavelets start on a sphere of radius \(R\) about S. Their envelope is a sphere of radius \(R + vt\) about S. The construction carries the shape of the wavefront forward. It will also turn a wavefront, wherever part of it is slowed down.

Deeper

Each wavelet is a full sphere, so why is there no wavefront travelling backwards? Huygens simply ignored the backward envelope. In 1818 Augustin Fresnel, and later Gustav Kirchhoff, showed that a wavelet is strongest straight ahead and fades to nothing straight back. The backward wave never forms.

Checkpoint · numericUnanswered

A plane wavefront travels through a large block of glass of \(\mu = 1.5\). How far does it move in \(1\,\text{ns}\), in cm?

cm± 2 %
Reflection and refraction by wavefronts
Maths you need

A wavefront meets a surface

Now let a plane wavefront AB arrive at a flat surface at an angle. The end A touches the surface first. The end B still has a distance BC to travel before it reaches the surface at C. In air, at speed \(v_1\), that takes a time \(t = BC/v_1\). During that time, the wavelet from A has been growing.

If the second medium is glass, the wavelet from A grows inside the glass at the smaller speed \(v_2\). In the time \(t\) it reaches a radius \(AD = v_2 t\). The new wavefront in the glass is the tangent from C to this wavelet, the line CD. Play Fig 1.2 and watch the front turn.

A wavefront meets a surfaceA plane wavefront AB travels towards a flat surface at an angle of incidence of 60 degrees. When played, the front sweeps along the surface from A to C. In the time the end B takes to reach C, a secondary wavelet from A grows to the radius AD. With the chip for glass of refractive index 1.5, the wavelet in the glass is only two thirds of BC, so the new wavefront CD is turned, and the ray bends to 35.3 degrees. With the chip for a mirror, the wavelet from A grows above the surface to AD = BC, and the reflected front leaves at 60 degrees. A second wavelet from the midpoint of AC touches the same new front. glass, μ = 1.5 air A B C D
Fig 1.2Press play. The wavefront AB meets the surface at \(i = 60°\). While B travels to C, the wavelet from A grows to AD. In glass of \(\mu = 1.5\), AD is only two thirds of BC, so the new front CD is turned and the ray bends to \(35.3°\). A wavelet from the middle of AC touches the same front. With the mirror chip, AD equals BC and the front leaves at \(60°\).

The two right triangles in Fig 1.2 give the law of refraction at once. Each shares the side AC. The angle between the wavefront and the surface equals the angle between the ray and the normal. Each pair is turned from the other by \(90°\).

Deriving \(\dfrac{\sin i}{\sin r} = \dfrac{v_1}{v_2} = \mu\) step 1 of 5
1

\[ BC = v_1 t, \qquad AD = v_2 t \]

Why. in the same time \(t\), the end B travels in air at \(v_1\) and the wavelet from A grows in glass at \(v_2\).

This is Snell's law, and now it comes with a reason. The ratio of the sines is a ratio of speeds, so the refractive index measures how much light slows down. The wave picture predicts that light is slower in glass and water. Newton's particles, to bend towards the normal, would have to go faster. The measurement settled it, as the story below tells.

RememberSnell's law from wavefronts
\[ \dfrac{\sin i}{\sin r} = \dfrac{v_1}{v_2} = \dfrac{\lambda_1}{\lambda_2} = \dfrac{\mu_2}{\mu_1} \]
Holds whena plane wavefront crossing a flat boundary between two transparent media; \(i\) and \(r\) are measured from the normal.
Symbols\(v_1, v_2\) the speeds of light in the two media; \(\lambda_1, \lambda_2\) the wavelengths there; \(\mu_1, \mu_2\) the refractive indices
Unitsspeeds in m/s, wavelengths in nm or m; the ratios have no unit

For reflection, the wavelet from A grows in the same medium, at the same speed \(v_1\). So in the time \(t\), \(AD = BC = v_1 t\). The right triangles ABC and CDA share the side AC and have \(AD = BC\), so they are congruent. Their angles at A and at C are equal, and so the angle of reflection equals the angle of incidence.

ExampleA wavefront enters glass

A plane wavefront in air meets a flat glass surface (\(\mu = 1.5\)) at an angle of incidence of \(30°\). The points A and C where its two ends touch the surface are \(6\,\text{cm}\) apart. Find BC, AD, the time between the two touches, and the angle of refraction.

Reveal one step at a time and finish the rest yourself.

Speed, wavelength and frequency in glass

The frequency does not change. In Fig 1.2, one crest reaches the surface for each crest that enters the glass, so crests leave the surface at the rate they arrive. The speed falls by the factor \(\mu\), so the wavelength \(\lambda = v/f\) falls by the same factor. Light of \(600\,\text{nm}\) in air has \(f = 5 \times 10^{14}\,\text{Hz}\). In glass of \(\mu = 1.5\) it travels at \(2 \times 10^8\,\text{m/s}\), with a wavelength of \(400\,\text{nm}\) and the same frequency.

CheckpointUnanswered

Light of \(600\,\text{nm}\) passes from air into glass of \(\mu = 1.5\). Which set gives its speed, wavelength and frequency in the glass?

CheckpointUnanswered

In Huygens' construction for reflection, why is the radius AD of the wavelet from A equal to BC?

A lens turns a wavefront

A plane wavefront that falls on a convex lens meets glass of different thickness at different heights. The lens is thickest at the middle and thin at the edge. Light is slower in the glass, so the middle of the front is held back the most. The edges get ahead, and the front comes out curved inwards: a sphere that closes in on the focus.

A convex lens turns a plane wavefront into a spherePlane wavefronts, drawn as straight vertical lines, arrive from the left and pass through a convex lens. Light is slower in glass, and the lens is thickest at the middle, so the middle of each front is held back most. The fronts that leave are arcs of circles centred on the focus F, getting smaller as they close in on it. Three rays, at right angles to the fronts, meet at F. F plane wavefront converging on F
Fig 1.3Plane wavefronts enter a convex lens of focal length \(6\,\text{cm}\) and leave as spheres centred on the focus F, shrinking as they converge. The rays, always at right angles to the fronts, meet at F.

The delays are tiny. Take a lens \(4\,\text{mm}\) thick at the centre and thin at the edge, of glass \(\mu = 1.5\). Light through the centre loses \((\mu - 1) \times 4\,\text{mm}\) \(= 2\,\text{mm}\) of air path, a delay of \(2 \times 10^{-3}/(3 \times 10^8)\) \(\approx 6.7 \times 10^{-12}\,\text{s}\). That is a few thousand periods of the wave, enough to curve the front into a sphere. A concave lens, thicker at the edge, holds back the edges and gives a diverging sphere.

Checkpoint · in your own wordsUnanswered

A plane wavefront passes through a convex lens. What is the shape of the wavefront that emerges? Explain it with the speed of light in glass.

Story · Christiaan Huygens and Léon Foucault, 1678 to 1850
A treatise on light, and a measurement that waited

In 1678 the Dutch scientist Christiaan Huygens read his ideas on light to the Academy of Sciences in Paris. He published them in 1690 as his Treatise on Light. With secondary wavelets he explained reflection, refraction and even the double images of a crystal of Iceland spar. His theory needed light to be slower in glass and water, while Newton's particles needed it to be faster. Nobody could measure the speed of light in water for another 160 years. In 1850 Léon Foucault, in Paris, used a fast rotating mirror to compare it in air and in water. Light was slower in water, exactly as the wave theory required.

Now return to the pond. Each ripple builds the next, because every point it reaches starts a wavelet of its own, like the bobbing leaf. Far from the splash, a short piece of a big circle is almost a straight line, a plane wavefront. Near the bank the water is shallow and the ripples slow down. The part of a ripple that reaches the shallows first is held back. So the ripple turns, exactly as light turns at the surface of glass.

Exam traps
  1. Taking a ray and a wavefront as two different kinds of light.
    They describe the same light. A ray is the normal to the wavefronts; the wavefront shows where the phase is the same.
  2. Letting the secondary wavelets grow at the speed of light in vacuum inside glass.
    Each wavelet grows at the speed of the medium it is in, \(c/\mu\). That slower growth is what turns the front.
  3. Saying that the frequency of light changes when it enters glass.
    The frequency is fixed by the source. The speed and the wavelength fall by \(\mu\); the frequency does not change.
  4. Reading the refractive index as \(v_2/v_1\).
    \(\sin i/\sin r = v_1/v_2\). The medium in which light is slower has the larger \(\mu\).