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Archimedes' Principle · Lesson 2 of 5

Floating: the Law of Flotation

14 min read3 ideas7 checks2 figures to playBy Asheshanand Acharya
What you will learn 0 / 3
Law of flotation
Look around
A ship of steel and a nail of steel

At the container terminal of Mumbai port, a ship made of thousands of tonnes of steel floats with stacks of containers on its deck. A steel nail dropped over its side goes straight to the bottom of the harbour. Both are steel, and steel is nearly eight times as dense as water.

you will see why the ship floats while the nail sinks, and find how deep a ship rides with its load.

Floating is a balance

Let go a body less dense than water with its bottom just touching the surface. At first almost none of it is under water, and the buoyant force is tiny. So the body sinks. As more of it goes under, it displaces more water, and the buoyant force grows. The body stops sinking when the buoyant force has grown to equal its weight. This state of balance is called flotation.

A wooden cube let go at the surfaceA wooden cube of side 10 centimetres and density 600 kilograms per cubic metre is let go with its bottom face just touching the water. Its weight W is 6 newtons. The buoyant force F_B is 1 newton for every centimetre of depth d under water. The cube sinks, overshoots to about 8.4 centimetres, bobs up and down and settles with 6 centimetres under water, where F_B equals W. A graph on the right plots F_B against d as a straight line, with W as a dashed level line; a dot moves along the line and comes to rest where the two cross. The motion is slowed down about five times. W 2468101224681012Od (cm)F (N) FB W d = 0.0 cm, FB = 0.0 N, W = 6.0 N
Fig 2.1A wooden cube of side \(10\,\text{cm}\) and density \(600\,\text{kg/m}^3\) is let go with its bottom just touching the water. Press play. \(F_B\) grows by \(1\,\text{N}\) for every centimetre of depth \(d\) under the surface, and the graph plots it against \(d\). The tank is wide, so the level hardly changes. The motion is slowed down about five times.

The cube weighs \(600 \times 0.001 \times 10 = 6\,\text{N}\). Its base has an area of \(0.01\,\text{m}^2\), so each centimetre under water displaces \(10^{-4}\,\text{m}^3\) of water, which weighs \(1\,\text{N}\). The buoyant force therefore reaches \(6\,\text{N}\) at \(d = 6\,\text{cm}\), where the line of the graph crosses \(W\). The cube arrives there moving, so it overshoots to about \(8.4\,\text{cm}\) and bobs. Water drag makes the bobbing die away, and it settles at \(6\,\text{cm}\).

law 2.1
The law of flotation

A body floating at rest in a fluid displaces a weight of fluid equal to its own weight.

RememberLaw of flotation
\[ \rho_f\, V_{sub}\, g = \rho_b\, V g = mg \]
Holds whena body floating at rest, with only its weight and the buoyant force acting on it.
Symbols\(\rho_f\) density of the fluid, \(V_{sub}\) volume under the surface, \(\rho_b\) average density of the body, \(V\) its whole volume, \(m\) its mass
Unitsevery term in N; densities in kg/m³, volumes in m³
ExampleA boat takes on cargo

A boat of mass \(200\,\text{kg}\) floats on a lake. (a) What volume of water does it displace? (b) Cargo of \(100\,\text{kg}\) is put in it. What volume does it displace now? (c) The boat has vertical sides near the waterline, and its waterline area is \(2\,\text{m}^2\). By how much does it sink when the cargo is loaded?

Try it on paper first. The solution is one tap away when you are ready.
CheckpointUnanswered

A ship sails from a river into the sea, where the water is denser. What happens to the buoyant force on it?

Fraction submerged

How much is under

Divide both sides of the law of flotation by \(\rho_f V g\). The fraction of the body under the surface is the ratio of the two densities. Wood of \(600\,\text{kg/m}^3\) floats with \(0.6\) of its volume under water. In oil of \(800\,\text{kg/m}^3\) it floats with \(600/800 = 0.75\) under. In a lighter liquid more of the body must go under to displace the same weight.

RememberFraction submerged
\[ \dfrac{V_{sub}}{V} = \dfrac{\rho_b}{\rho_f} \]
Holds whena body floating at rest, with \(\rho_b < \rho_f\). If \(\rho_b = \rho_f\) it floats fully under at any depth; if \(\rho_b > \rho_f\) it sinks.
Symbols\(V_{sub}\) volume under the surface, \(V\) whole volume, \(\rho_b\) average density of the body, \(\rho_f\) density of the liquid
Unitsa pure number
How much of a floating block is underA block with sides of 10 centimetres floats in a tank. Choose fresh water of density 1000, sea water of density 1025 or oil of density 800 with the chips, and set the density of the block with the slider. While the block is less dense than the liquid it floats, and the fraction of it under the surface is its density divided by the density of the liquid; a double arrow marks the depth under. When the block is as dense as the liquid or denser, it goes to the bottom. d fraction under = 600/1000 = 0.60
SimA block with sides of \(10\,\text{cm}\) in fresh water (\(1000\,\text{kg/m}^3\)), sea water (\(1025\,\text{kg/m}^3\)) or oil (\(800\,\text{kg/m}^3\)). Set the density of the block with the slider, and choose the liquid with the chips. The double arrow marks the depth \(d\) under the surface.

Set the slider in the sim above to \(900\,\text{kg/m}^3\), a round value for ice. In fresh water \(0.90\) of the block is under. In sea water only \(900/1025 = 0.88\) is under, so a little more shows. This is the hidden bulk of an iceberg: almost nine tenths of it lies below the sea. Now set \(1000\) in fresh water. The block hangs fully under, wherever it is put. Above \(1000\) it goes to the bottom.

Checkpoint · numericUnanswered

A body floats with \(60\,\%\) of its volume under water, and with \(75\,\%\) of its volume under the surface of another liquid. Find the density of the other liquid, in kg/m³.

kg/m³± 2 %
CheckpointUnanswered

A cylinder \(20\,\text{cm}\) tall floats upright in water with \(16\,\text{cm}\) of its height under. It is moved to oil of density \(800\,\text{kg/m}^3\). How does it float?

Pushing a float under

A cube of side \(10\,\text{cm}\) and density \(500\,\text{kg/m}^3\) floats with half of it, \(5\,\text{cm}\), under water. Push it down until it is fully under. Now it displaces \(10^{-3}\,\text{m}^3\) of water, and the buoyant force is \(10\,\text{N}\). Its weight is only \(5\,\text{N}\), so your hand must push down with the difference, \(5\,\text{N}\). That is the weight of the extra water the cube now displaces.

Checkpoint · numericUnanswered

A wooden block of volume \(2 \times 10^{-3}\,\text{m}^3\) and density \(600\,\text{kg/m}^3\) floats in water. Take \(g = 10\,\text{m/s}^2\). What downward force holds it just fully under the surface, in newtons?

N± 2 %

River water and sea water

Sea water, at about \(1025\,\text{kg/m}^3\), is denser than river water. So a ship floats higher in the sea. A ship loaded at Kolkata port, on the Hooghly, rises as it reaches the salt water of the Bay of Bengal. Every cargo ship carries a load line painted on its hull. Its marks show how deep the ship may lie in fresh water and in sea water.

Checkpoint · numericUnanswered

A loaded ship of mass \(10\,000\,\text{t}\) floats at Kolkata port in river water of \(1000\,\text{kg/m}^3\). Its waterline area is \(2000\,\text{m}^2\), and its sides are vertical near the waterline. By how much does it rise when it reaches sea water of \(1025\,\text{kg/m}^3\), in cm?

cm± 2 %
Why a steel ship floats
Maths you need

A bowl of steel

Steel is \(7.8\) times as dense as water, so a solid lump of steel sinks. Press the same steel into a bowl, and it encloses a large volume of air. What decides floating is the average density of the body: its total mass divided by the whole volume it encloses, the air included. A body floats when its average density is less than the density of the liquid.

The same steel as a block and as a bowlA tank of water. In the first chip a solid steel block of 30 cubic centimetres and 234 grams lies on the bottom: it can push aside only 30 grams of water, so it sinks. In the second chip the same 234 grams of steel is pressed into a square bowl 10 centimetres across and 5 centimetres high, with walls a millimetre thick. The bowl floats with 2.34 centimetres under water, where it pushes aside 234 grams of water, its own weight. The water does not enter the bowl. steel 234 g of steel, 30 cm³: it sinks
Fig 2.2\(234\,\text{g}\) of steel, first as a solid block of \(30\,\text{cm}^3\). Then the same steel is pressed into a square bowl \(10\,\text{cm}\) across and \(5\,\text{cm}\) high, with walls about a millimetre thick. Choose a chip.

The block in Fig 2.2 can push aside at most \(30\,\text{cm}^3\) of water, which weighs \(30\,\text{g}\), against its own \(234\,\text{g}\). So it sinks. The bowl encloses \(10 \times 10 \times 5 = 500\,\text{cm}^3\), and its average density is \(234/500 = 0.47\,\text{g/cm}^3\), less than that of water. It floats with \(234/100 = 2.34\,\text{cm}\) of its depth under water, where it displaces \(234\,\text{g}\) of water. A steel ship is this bowl made enormous.

Checkpoint · numericUnanswered

A hollow steel ball has a mass of \(2\,\text{kg}\) and an outer volume of \(4 \times 10^{-3}\,\text{m}^3\). It floats in water. What fraction of its volume is under the surface?

± 2 %

Return to the ship at Mumbai port. Its steel hull encloses a huge volume of air, so the average density of hull and cargo together stays below that of sea water. It sinks until it has displaced its own weight, and then it floats. The nail has no air inside. Its average density is that of steel, and no depth of water can hold it up.

EstimateUnanswered

A loaded container ship at Mumbai port has a mass of about \(50\,000\,\text{t}\). Taking sea water as \(1025\,\text{kg/m}^3\), estimate the volume of sea water it displaces, in cubic metres.

m³rough value is enough
Story · Samuel Plimsoll, 1876
The line that saved sailors

In the 1860s many British cargo ships sailed so overloaded that they sank in the first storm. Some owners insured such ships for more than their worth, and the sailors paid with their lives. Samuel Plimsoll, a member of Parliament, fought a long campaign against these coffin ships. In 1876 a law required British ships to carry a load line on the hull. The mark still bears his name.

Exam traps
  1. Using the whole volume of a floating body in \(F_B = \rho_f V g\).
    Only the part under the surface displaces fluid. Use \(V_{sub}\).
  2. Thinking a ship rides higher in the sea because the buoyant force there is larger.
    The buoyant force equals the weight in both. The denser sea supplies it from a smaller volume.
  3. Deciding whether a steel ship floats from the density of steel.
    Use the average density, the total mass over the whole volume the hull encloses.