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Vectors · Lesson 1 of 6

Scalars and Vectors

14 min read3 ideas7 checks1 figure to playBy Asheshanand Acharya
What you will learn 0 / 3
Scalars and vectors
Look around
Seven kilometres on the meter, five on the map

An auto-rickshaw leaves a hotel in Jaipur. It drives \(3\,\text{km}\) east along one road, turns left, and drives \(4\,\text{km}\) north to the railway station. The meter charges for \(7\,\text{km}\). On the map, the station is only \(5\,\text{km}\) from the hotel in a straight line. Both numbers are correct. They answer two different questions.

you will be able to tell which quantities need a direction, and find the displacement of a trip that turns.

Numbers that are complete

Some quantities are fully described by a number and a unit. A mass of \(2\,\text{kg}\), a time of \(5\,\text{s}\), a temperature of 30 °C and an energy of \(10\,\text{J}\) need nothing more. Such a quantity is a scalar. Two scalars of the same kind add as ordinary numbers. A \(2\,\text{kg}\) bag and a \(3\,\text{kg}\) bag together always have a mass of \(5\,\text{kg}\).

Quantities that need a direction

Other quantities are not complete without a direction. A displacement of \(4\,\text{km}\) could end at the station or at the airport. A force of \(50\,\text{N}\) could lift a bag or push it down. Such a quantity is a vector. Its size is called its magnitude, and the magnitude is never negative. A vector is drawn as an arrow. The length of the arrow shows the magnitude on a chosen scale, and the arrow points in the direction of the quantity.

definition 3.1
Scalar and vector

A scalar is a physical quantity that has magnitude only; scalars of one kind add as ordinary numbers. A vector is a physical quantity that has both magnitude and direction, and that adds by the triangle rule of the next lesson.

In print a vector is written in bold, \(\mathbf{A}\). By hand it is written with an arrow, \(\vec A\). The magnitude is written \(|\vec A|\), or simply \(A\) in italics without the arrow. An arrow of length one that points along \(\vec A\) is called the unit vector along \(\vec A\), written \(\hat A\) and read "A hat". A unit vector carries a direction and nothing else, so it has no unit. Every vector is its magnitude times its unit vector.

RememberA vector is its magnitude times its direction
\[ \vec A = A\,\hat A, \qquad A = |\vec A| \ge 0 \]
Holds whenfor every vector that is not zero. The unit vector \(\hat A\) has magnitude 1 and no unit; the magnitude \(A\) carries the unit.
Symbols\(\vec A\) the vector; \(A\) its magnitude; \(\hat A\) the unit vector along \(\vec A\)
Units\(A\) in the unit of the quantity (m, m/s, N); \(\hat A\) has no unit

Distance and displacement

The meter of the auto-rickshaw measures the length of the road it covers. That length is the distance, a scalar. The \(3\,\text{km}\) and the \(4\,\text{km}\) simply add to \(7\,\text{km}\). The map measures the straight arrow from the hotel to the station. That arrow is the displacement, a vector. Its two parts are at right angles, so its magnitude is \(\sqrt{3^2 + 4^2} = 5\,\text{km}\).

Distance keeps growing, displacement comes backA walker goes once round a rectangular track 80 m by 40 m in a park, starting at S and walking east, north, west and south at 20 m per second of the animation. The walked part of the track is traced as a line whose length is the distance. An arrow from S to the walker is the displacement. The distance grows steadily to 240 m. The displacement grows to 89 m at the far corner, then shrinks, and is zero when the walker is back at S.person walking 80 m 40 m S distance = 0 m, displacement = 0 m
Fig 1.1A walk once round a track \(80\,\text{m}\) by \(40\,\text{m}\) in a park. Press play. The blue trace is the path covered, and its length is the distance. The violet arrow from S is the displacement. The distance only grows, to \(240\,\text{m}\). The displacement grows to \(89\,\text{m}\) at the far corner and shrinks to zero at S.

The distance of a journey can only grow. The displacement can grow, shrink and turn, because it depends only on where the body is now and where it started. At the far corner of the track the displacement is \(\sqrt{80^2 + 40^2} = 89\,\text{m}\). Back at the start it is zero, although the walker has covered \(240\,\text{m}\).

Common mistake

A direction alone does not make a quantity a vector. An electric current flows along a wire, yet two currents that meet at a junction simply add as numbers, whatever the angle between the wires. So current is a scalar. A large rotation is not a vector either. Turn a book through \(90°\) about two different axes in two different orders, and it ends in two different positions. A vector must add by the triangle rule, and in any order.

CheckpointUnanswered

Which of these quantities is a vector?

CheckpointUnanswered

A current of \(2\,\text{A}\) in one wire and a current of \(3\,\text{A}\) in another wire flow into a junction at an angle of \(60°\). How much current leaves the junction?

Equal negative and zero vectors

Equal vectors

Two vectors are equal when they have the same magnitude and the same direction. Their position does not matter. Two Metro trains running side by side on parallel tracks at \(20\,\text{m/s}\) have equal velocities, although they are in different places. So a vector may be slid anywhere in a drawing, as long as its length and direction stay the same. The next lesson uses this freedom to add vectors.

The negative of a vector and the zero vector

The vector \(-\vec A\) has the same magnitude as \(\vec A\) and points the opposite way. A velocity of \(20\,\text{m/s}\) east has the negative \(20\,\text{m/s}\) west. A vector added to its own negative gives a vector of magnitude zero. This is the zero vector, written \(\vec 0\). The walk round the park ends with a zero displacement.

Two vectors that point the same way are called parallel. Two that point opposite ways are antiparallel. The angle between two vectors is measured with their tails together, and it lies between \(0°\) and \(180°\). Parallel vectors are at \(0°\), antiparallel vectors at \(180°\), and perpendicular vectors at \(90°\).

CheckpointUnanswered

Two cars on the Mumbai-Pune expressway move at \(25\,\text{m/s}\), one in each carriageway, in opposite directions. Which statement is correct?

Multiplying a vector by a number

A vector times a number

A vector can be multiplied by an ordinary number \(k\). The product \(k\vec A\) has a magnitude \(|k|\) times that of \(\vec A\). If \(k\) is positive, \(k\vec A\) points along \(\vec A\). If \(k\) is negative, it points the opposite way. At \(k = 0\) it is the zero vector. The number \(k\) may carry a unit of its own. Then the product is a new physical quantity.

Multiplying a vector by a numberA vector A, 3 units right and 1.5 units up, is drawn at the upper left. A slider sets a number k from minus 2 to 2. The arrow kA is drawn from the point O along the dashed line of A. For k greater than 1 it is longer than A, for k between 0 and 1 shorter, at k = 0 it vanishes, and for negative k it points the opposite way. Its length is always the size of k times the length of A. A kA O k = 1.5, |kA| = 1.5A same direction as A
SimMove the slider for the number \(k\). The blue arrow \(k\vec A\) always lies on the dashed line of \(\vec A\). It stretches for \(k > 1\), shrinks for \(0 < k < 1\), vanishes at \(k = 0\) and points the other way for negative \(k\).

Physics is full of such products. Momentum is \(\vec p = m\vec v\), and the mass \(m\) is positive, so momentum always points along the velocity. The weight of a body is \(m\vec g\), along the downward \(\vec g\). The force on a charge \(q\) in an electric field is \(\vec F = q\vec E\). For an electron, \(q\) is negative, so the force points against the field.

RememberA vector times a number, and the unit vector
\[ \begin{gathered}|k\vec A| = |k|\,A \\ \hat A = \dfrac{\vec A}{A}\end{gathered} \]
Holds whenfor any real number \(k\). The unit vector \(\hat A = \vec A / A\) exists only when \(\vec A\) is not the zero vector.
Symbols\(k\) a number, possibly with a unit; \(\vec A\) a vector of magnitude \(A\); \(\hat A\) the unit vector along \(\vec A\)
Units\(k\vec A\) has the unit of \(k\) times the unit of \(\vec A\); \(\hat A\) has no unit

The average velocity is the plainest example. It is a displacement divided by a time. The derivation below shows why it must point along the displacement.

Deriving \(\vec v_{avg} \parallel \Delta\vec r\) step 1 of 4
1

\[ \vec v_{avg} = \dfrac{\Delta\vec r}{\Delta t} \]

Why. the average velocity is the displacement \(\Delta\vec r\) over the time interval \(\Delta t\).

CheckpointUnanswered

A vector \(\vec A\) has magnitude \(4\,\text{N}\) and points north. What is \(-3\vec A\)?

CheckpointUnanswered

An electron, of charge \(-1.6\times10^{-19}\,\text{C}\), is in an electric field of \(1000\,\text{N/C}\) that points east. What is the force \(\vec F = q\vec E\) on it?

ExampleBack to physics: out, then partly back

This is the worked example "Out, then partly back" of Motion in One Dimension, lesson 3, done with the tool. A particle starts at \(x = 0\). It moves to \(x = +5\,\text{m}\) in \(2\,\text{s}\). It then turns back and reaches \(x = +2\,\text{m}\) after another \(3\,\text{s}\). Find the average speed and the average velocity for the whole \(5\,\text{s}\).

Reveal one step at a time and finish the rest yourself.
Checkpoint · numericUnanswered

An auto-rickshaw drives \(6\,\text{km}\) east and then \(8\,\text{km}\) north. Find the magnitude of its displacement, in km.

km± 2 %
Checkpoint · in your own wordsUnanswered

A walker goes once round a track and ends where she started. Why is her distance \(240\,\text{m}\) while her displacement is zero?

The auto-rickshaw of the opening can now be read. The meter adds two scalars, \(3 + 4 = 7\,\text{km}\), because it measures the road. The map shows one vector, the displacement from the hotel to the station. Its magnitude is \(5\,\text{km}\), and it points \(53°\) north of east, since \(\tan^{-1}(4/3) = 53°\).

In the world
Where this tool works in physics

Motion in One Dimension begins with this distinction: distance and speed are scalars, while displacement and velocity are vectors. Motion in Two Dimensions writes position and displacement as arrows in a plane. In Gravitation and in Electrostatics, the potentials of several bodies add as plain numbers. Their fields are vectors and add as arrows. Electric Flux and Gauss's Law turns an area into a vector, with its direction along the normal to the surface.

Exam traps
  1. Calling a quantity a vector because it has a direction, like the current in a wire.
    A vector must also add by the triangle rule. Currents at a junction add as numbers, so current is a scalar.
  2. Writing a negative magnitude, such as \(|\vec v| = -5\,\text{m/s}\).
    A magnitude is never negative. A minus sign belongs to a component or to a direction, never to the size.
  3. Treating two vectors as unequal because they are drawn in different places.
    Only the magnitude and the direction decide equality. An arrow may be slid parallel to itself.

Where this tool works in the book

The physics that leans on this lesson. Each card opens the topic where the tool is at work.