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Potential Energy

15 min read4 ideas7 checks3 figures to playBy Asheshanand Acharya
What you will learn 0 / 4
Potential energy is stored in an arrangement
Look around
The tank on the roof

In many Indian homes a motor pumps water every morning from an underground sump to a tank on the roof. Then the motor stops. For the rest of the day the taps run without any pump at all. The water in the tank is at rest, yet it clearly holds something that the motor put there.

you will find how much energy a tank of water on the roof holds. The answer never depends on where you measure the height from.

Energy with nowhere to be seen

In the chapter on Work, Kinetic Energy and Power, work was the transfer of energy by a force. The energy of a moving body is its kinetic energy \(K = \tfrac12 mv^2\), where \(m\) is the mass and \(v\) the speed. Now lift a brick slowly from the floor onto a shelf. You do work on it, but at the end the brick is at rest. Its kinetic energy is zero.

The energy has not vanished. Let the brick fall and it reaches the floor with exactly the speed that this energy would give it. So the energy was stored while the brick sat on the shelf. It was stored in the arrangement, in the brick being high above the Earth. Energy stored in an arrangement is called potential energy, written \(U\).

A stretched catapult, a wound clock spring and a compressed air cushion all store energy in the same way. Nothing in them moves and nothing is hot. The energy is in the shape: how far the parts are from where they would like to be.

How a change in potential energy is measured

The Earth pulls on the brick with its weight \(mg\), where \(g = 10\,\text{m/s}^2\) is the acceleration due to gravity. When the brick rises, gravity does negative work on it. When the brick falls, gravity does positive work and speeds it up. We define the change in potential energy as the negative of the work done by this force.

definition 2.1
Change in potential energy

A system changes from one arrangement to another. The change in its potential energy is the negative of the work \(W\) done by the force that stores the energy: \(\Delta U = U_f - U_i = -W\).

The minus sign carries the meaning. When gravity does positive work, as in a fall, the potential energy decreases and the body gains speed. When gravity does negative work, as in a lift, the potential energy increases. Only some forces can store energy this way; the next lesson shows which. Gravity and the force of a spring are two of them.

CheckpointUnanswered

While a coconut falls from a tree, gravity does \(+12\,\text{J}\) of work on it. What is the change in the potential energy of the coconut and the Earth?

Gravitational potential energy and its zero

Gravitational potential energy

Lift a body of mass \(m\) through a height \(h\) near the Earth's surface. The weight \(mg\) points down and the displacement points up, so gravity does work \(-mgh\). The change in potential energy is therefore \(\Delta U = -(-mgh) = +mgh\). The path does not matter: gravity's work depends only on the change in height.

Now choose a level and call it \(U = 0\). This level is the reference level. A body at a height \(h\) above it then has \(U = mgh\). A body below it has a negative \(h\), and so a negative \(U\). A negative potential energy is not a mistake. It only means the body is below the level you chose.

RememberGravitational potential energy near the Earth
\[ U = mgh, \qquad \Delta U = mg\,\Delta h \]
Holds whennear the Earth's surface, where \(g\) is constant; \(h\) is measured upward from the chosen reference level.
Symbols\(U\) potential energy of the body and the Earth, \(m\) mass, \(g\) acceleration due to gravity, \(h\) height above the reference level, \(\Delta h\) change in height
Units\(U\) in J when \(m\) is in kg, \(g\) in m/s² and \(h\) in m
One fall, three choices of zeroA 0.5 kilogram ball is held 3 metres above the floor and falls onto a table top 1 metre above the floor. Chips put the zero of potential energy at the floor, at the table top or at the ceiling 4 metres up. The two values of U change with the choice, 15 and 5 joules, 10 and 0 joules, or minus 5 and minus 15 joules, but the change is minus 10 joules every time.table, side viewball (shaded) A B U = 0 at A: U = 15 J at B: U = 5 J change: ΔU = −10 J
Fig 1.1A \(0.5\,\text{kg}\) ball falls from A, \(3\,\text{m}\) above the floor, to B on a table top \(1\,\text{m}\) above the floor. Choose where \(U = 0\). The two values of \(U\) change with every choice, but the change \(\Delta U\) is \(-10\,\text{J}\) each time.

Try the three choices in Fig 1.1. With the floor as zero, \(U\) is \(15\,\text{J}\) at A and \(5\,\text{J}\) at B. With the table top as zero, it is \(10\,\text{J}\) and \(0\). With the ceiling as zero, both values are negative, \(-5\,\text{J}\) and \(-15\,\text{J}\). In all three cases the ball loses \(10\,\text{J}\) of potential energy in the fall. That \(10\,\text{J}\) is what becomes kinetic energy, so the speed at B is the same for every choice.

principle 2.1
Only changes in potential energy are physical

The zero of potential energy may be placed anywhere. No experiment measures \(U\) itself; every measurable result depends only on a change \(\Delta U\), which is the same for every choice of zero.

Common mistake

Choose the reference level once, at the start of a problem, and write it down. Measuring one height from the floor and another from the table top in the same problem gives a wrong \(\Delta U\).

ExampleThe energy in the roof tank

A motor lifts \(1000\,\text{kg}\) of water from a sump \(2\,\text{m}\) below the ground to a tank \(10\,\text{m}\) above the ground. Take \(g = 10\,\text{m/s}^2\). How much potential energy does the water gain? Does the answer depend on the reference level?

Reveal one step at a time and finish the rest yourself.
Checkpoint · numericUnanswered

A \(2\,\text{kg}\) school bag is lifted from the floor onto a shelf \(1.5\,\text{m}\) high. Take \(g = 10\,\text{m/s}^2\). By how much does the potential energy increase, in joules?

J± 2 %
CheckpointUnanswered

A ball is held \(2\,\text{m}\) above a table that stands \(1\,\text{m}\) above the floor. Asha takes the floor as the reference level, and Ravi takes the table top. The ball is dropped onto the table. On what do they disagree?

Elastic potential energy of a spring
Maths you need

The energy in a spring

A spring stretched by \(x\) from its natural length pulls back with a force of size \(kx\). Here \(k\) is the spring constant, in N/m. The force always points towards the natural length, so we write it as \(F = -kx\). In the chapter on Work you found the work done by this force from \(x = 0\) to \(x\). It is the area of a triangle under the force-extension graph, \(-\tfrac12 kx^2\).

So the potential energy stored in the spring is \(U = +\tfrac12 kx^2\), with \(U = 0\) at the natural length. The square has a plain meaning. A compression \(x = -0.2\,\text{m}\) gives the same energy as a stretch \(x = +0.2\,\text{m}\). The spring stores energy for being deformed, and it does not care in which direction.

RememberElastic potential energy of a spring
\[ U = \tfrac12 kx^2 = \dfrac{F^2}{2k} \]
Holds whenan ideal light spring obeying Hooke's law, with \(U = 0\) at the natural length. Here \(x\) is the stretch or compression, and \(F = kx\) is the force in the spring.
Symbols\(U\) energy stored, \(k\) spring constant, \(x\) change in length from the natural length, \(F\) size of the force in the spring
Units\(U\) in J, \(k\) in N/m, \(x\) in m, \(F\) in N
A spring stretched or compressedA block on a smooth floor is fixed to a wall by a spring of constant 200 newtons per metre and natural length 1 metre. Chips compress it by 0.2 metre, leave it at its natural length, stretch it by 0.2 metre or by 0.4 metre. The spring force on the block always points back towards the natural length. The stored energy is 4 joules for both 0.2 metre cases and 16 joules for 0.4 metre, four times as much for twice the stretch.spring — natural (helical, parametric) x = 0 F = 40 N U U = ½kx² = 4.0 J
Fig 1.2A spring of \(k = 200\,\text{N/m}\) holds a block on a smooth floor. Choose a chip. A compression of \(0.2\,\text{m}\) and a stretch of \(0.2\,\text{m}\) both store \(4\,\text{J}\), while the force on the block reverses. A stretch of \(0.4\,\text{m}\) stores \(16\,\text{J}\), four times as much.

The last chip of Fig 1.2 shows the square at work. Doubling the stretch doubles the force, and the force acts over twice the distance. So the stored energy grows four times. Tripling the stretch would store nine times the energy.

CheckpointUnanswered

A spring stores \(5\,\text{J}\) when it is compressed by \(3\,\text{cm}\). How much does it store when it is stretched by \(6\,\text{cm}\)?

Springs in series and in parallel

Two springs joined end to end are springs in series. In the chapter Objects in Equilibrium you saw that one force \(F\) runs through both. So each spring stores \(U = F^2/2k\). The softer spring, with the smaller \(k\), stretches more and stores more energy. For two springs in series, \(U_1/U_2 = k_2/k_1\).

Two springs side by side, both fixed to the wall and to the block, are springs in parallel. They share one stretch \(x\), and their forces add: \(F = k_1x + k_2x\). So the pair acts as one spring of constant \(k = k_1 + k_2\). Each spring stores \(\tfrac12 k x^2\) with its own \(k\), so now the stiffer spring stores more, and \(U_1/U_2 = k_1/k_2\).

Two springs, in series and in parallelTwo light springs of constants 100 and 300 newtons per metre hold a block on a smooth floor, pulled by a steady 30 newtons. In series both springs carry 30 newtons, so the softer one stretches 0.3 metre and stores 4.5 joules while the stiffer one stretches 0.1 metre and stores 1.5 joules. In parallel both stretch by the same 0.075 metre, and the stiffer one stores more, 0.84 joule against 0.28 joule.spring — natural (helical, parametric) k1 k2 30 N U1 U2 U1 = 4.50 J, U2 = 1.50 J the softer spring stores more
Fig 1.3Springs of \(100\,\text{N/m}\) and \(300\,\text{N/m}\) hold a block pulled by \(30\,\text{N}\). In series each carries \(30\,\text{N}\): the soft spring stores \(4.5\,\text{J}\) and the stiff one \(1.5\,\text{J}\). In parallel both stretch \(0.075\,\text{m}\): now the stiff spring stores \(0.84\,\text{J}\) and the soft one \(0.28\,\text{J}\).

Cutting a spring

Cut a spring of natural length \(L\) and constant \(k\) into a piece of length \(L_1\). Under one force, every centimetre of the spring stretches by the same amount. So a piece stretches in proportion to its length, and a shorter piece is stiffer: \(k_1 L_1 = kL\). A spring cut in half has twice the spring constant.

RememberSprings in series, in parallel and cut
\[ \dfrac{1}{k_s} = \dfrac{1}{k_1} + \dfrac{1}{k_2}, \qquad k_p = k_1 + k_2, \qquad k_1 L_1 = kL \]
Holds whenlight ideal springs. In series the same force acts through both; in parallel both have the same stretch. A cut piece is part of a uniform spring.
Symbols\(k_s\) constant of the series pair, \(k_p\) constant of the parallel pair, \(k_1\), \(k_2\) constants of the two springs, \(k\) and \(L\) constant and natural length of the whole spring, \(L_1\) length of the cut piece
Unitsevery \(k\) in N/m, lengths in m or cm (the same unit on both sides)
ExampleCutting a spring and joining the pieces

A spring of constant \(200\,\text{N/m}\) and natural length \(60\,\text{cm}\) is cut into pieces of \(20\,\text{cm}\) and \(40\,\text{cm}\). Find the constant of each piece. The two pieces are then joined in parallel. Find the constant of the pair, and the energy stored in the short piece when it alone is stretched by \(5\,\text{cm}\).

Try it on paper first. The solution is one tap away when you are ready.
Checkpoint · numericUnanswered

Springs of \(200\,\text{N/m}\) and \(600\,\text{N/m}\) are joined in series and hold a \(3\,\text{kg}\) block at rest. Take \(g = 10\,\text{m/s}^2\). What is the total energy stored in the two springs, in joules?

J± 2 %
Checkpoint · select all that applyUnanswered

A spring of constant \(k\) is cut into two equal halves. Which statements are true?

Potential energy belongs to the pair

Whose energy is it?

We often say "the potential energy of the ball". That is a convenient short form. The energy is stored in the separation between the ball and the Earth, and it takes both of them to store it. Neither body owns it. The same is true of a spring joining two blocks: the energy is in the spring between them, not in either block.

The short form is harmless near the Earth for one reason. When a ball falls, the Earth also moves towards the ball, but its enormous mass keeps its motion tiny. Almost all the released energy goes to the ball. Two bodies of similar mass, such as two stars or two blocks joined by a spring, share the energy. Then the potential energy must be assigned to the pair.

Deeper

When a \(1\,\text{kg}\) ball and the Earth pull each other together, their momenta stay equal and opposite. Kinetic energy is \(p^2/2m\), so the two kinetic energies are in the inverse ratio of the masses. The Earth receives about \(1/(6 \times 10^{24})\) of the energy the ball receives, far too little to measure.

CheckpointUnanswered

Two blocks on a smooth floor are joined by a compressed spring and held still. When they are released, both blocks move off. Where was the energy stored?

Story · William Rankine, 1853
A name for stored energy

In 1853 the Scottish engineer William Rankine wrote a paper on how energy changes form. He needed a word for energy that sits in a body because of its position or shape, ready to become motion. He called it "potential energy", and he called the energy of motion "actual energy". The second name did not last; Kelvin's "kinetic energy" replaced it. Rankine's term stayed, and it is the \(U\) of this chapter.

In the world
Batteries made of mountains

A pumped-storage power station has two lakes, one high on a hill and one low in the valley. When electricity is cheap and plentiful, pumps lift water to the upper lake and store it as potential energy. When the demand is high, the water runs down through turbines and makes electricity again. India is building such stations, for example at Tehri in Uttarakhand, to store solar power made during the day for use at night.

Exam traps
  1. Measuring different heights from different levels in one problem.
    Fix one reference level at the start. Every \(h\) is measured from it, upward positive.
  2. Treating a negative potential energy as impossible.
    A negative \(U\) only means the body is below the chosen zero. Only changes in \(U\) matter.
  3. Using \(U = \tfrac12 kx\) or measuring \(x\) from the wall.
    \(U = \tfrac12 kx^2\), and \(x\) is the change in length from the natural length.
  4. Taking a cut piece to be softer than the whole spring.
    A shorter piece is stiffer: \(k_1 = kL/L_1\).