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Heat Engines and Their Efficiency

14 min read3 ideas5 checks1 figure to playBy Asheshanand Acharya
What you will learn 0 / 3
What a heat engine needs
Look around
The towers that pour out warm air

Drive past a coal power station, such as Vindhyachal in Madhya Pradesh or Korba in Chhattisgarh. The tallest things there are not the chimneys. They are the cooling towers, wide concrete shells with clouds of warm, moist air rising from them day and night. The station burns coal to make electricity, yet it seems to spend a great deal of effort getting rid of heat.

you will see why a power station must throw away most of the heat of its coal, and why no cleverer design can avoid it.

Heat into work, again and again

The chapter on the First Law showed that a gas can turn heat into work. Heat a gas under a piston and it expands and lifts the load. But one expansion is not an engine. The piston soon reaches the top of the cylinder and the work stops. A useful engine must do work over and over, for hours.

So the gas must be brought back to where it started, and then expand again. A series of processes that returns a system to its starting state is a cyclic process, or a cycle. On a p-V diagram a cycle is a closed loop. The gas that goes round the loop and does the work is the working substance.

Internal energy depends only on the state. After one full cycle the gas is back in its starting state, so its internal energy is unchanged: \(\Delta U = 0\). The first law, \(Q = \Delta U + W\), then gives \(Q_\text{net} = W_\text{net}\). Over a cycle, the net heat taken in equals the net work done. This is the whole idea of a heat engine.

Three parts of every heat engine

A heat engine takes heat \(Q_H\) from a hot body, the source, at temperature \(T_H\). It does work \(W\). It gives heat \(Q_C\) to a cold body, the sink, at temperature \(T_C\). Here \(Q_H\) and \(Q_C\) are both sizes, taken as positive numbers. Many books write \(Q_1\), \(Q_2\), \(T_1\) and \(T_2\) for the same four quantities. The workbook does so too.

The source and the sink are thermal reservoirs. A reservoir is so large that taking heat from it, or giving heat to it, does not change its temperature. The furnace of a power station is kept at a steady temperature by burning coal. The river or the air that carries heat away is so large that it hardly warms. So \(T_H\) and \(T_C\) stay fixed while the engine runs.

Over one cycle the working substance takes in \(Q_H\) and gives out \(Q_C\), so the net heat is \(Q_H - Q_C\). This equals the net work. So the heat engine obeys one energy balance, \(Q_H = W + Q_C\). The heat taken from the source is split into work and heat rejected. None of it is lost.

definition 5.1
Heat engine

A heat engine is a device that takes a working substance round a cycle. In each cycle it takes heat \(Q_H\) from a hot reservoir, does work \(W\), and gives heat \(Q_C\) to a cold reservoir, with \(Q_H = W + Q_C\).

CheckpointUnanswered

In one cycle, the gas of an engine takes in \(900\,\text{J}\) of heat and gives out \(600\,\text{J}\) of heat. What is the change in its internal energy over the cycle?

Thermal efficiency

How good is an engine?

Heat costs money: coal, diesel, petrol or gas. Work is what we want. So the natural measure of an engine is the fraction of the heat taken in that comes out as work. This fraction is the thermal efficiency, written \(\eta\) (the Greek letter eta).

RememberEfficiency of a heat engine
\[ \eta = \dfrac{W}{Q_H} = \dfrac{Q_H - Q_C}{Q_H} = 1 - \dfrac{Q_C}{Q_H} \]
Holds whenany heat engine working in a cycle; \(Q_H\) and \(Q_C\) are the sizes of the heat taken in and given out in one cycle, or in one second.
Symbols\(\eta\) efficiency, \(W\) net work per cycle, \(Q_H\) heat taken from the hot reservoir, \(Q_C\) heat given to the cold reservoir
Units\(\eta\) has no unit (often written as a percentage); \(W\), \(Q_H\), \(Q_C\) in J, or in W when taken per second

An engine takes \(1000\,\text{J}\) from the source and gives \(600\,\text{J}\) to the sink in each cycle. Its work is \(1000 - 600 = 400\,\text{J}\), and its efficiency is \(400/1000 = 0.40\), or \(40\,\%\). The second form of the formula shows the limit at once. The efficiency can be \(1\) only if \(Q_C = 0\), when nothing at all is given to the sink.

Where the heat of an engine goesAn energy-flow diagram. A hot source at temperature T_H gives heat Q_H to an engine, which does work W and rejects heat Q_C to a cold sink at T_C. The engine is the best possible one between the two temperatures. Beside it a bar shows where each 1000 joules of Q_H goes: the brown part is the work, the blue part the heat rejected. Two sliders set T_H from 400 to 900 kelvin and T_C from 250 to 400 kelvin. At 600 K and 300 K the efficiency is 0.50, so 500 joules become work and 500 joules are rejected. As T_C rises towards T_H the work shrinks to nothing; the rejected heat never reaches zero.TH = 600 K QH engine QC TC = 300 K W where each 1000 J goes W QC η = 1 − TC/TH = 0.50 W = 500 J, QC = 500 J
SimThe energy flow of the best engine that can work between a source at \(T_H\) and a sink at \(T_C\). Move the sliders. The bar shows where each \(1000\,\text{J}\) of \(Q_H\) goes: brown is the work, blue the heat rejected. Lesson 3 proves the rule that this engine follows, \(\eta = 1 - T_C/T_H\).

Try the sliders in the sim above. With the source at \(600\,\text{K}\) and the sink at \(300\,\text{K}\), even the best engine rejects half its heat. Raise \(T_H\) to \(900\,\text{K}\) and the work share grows to two thirds. Now raise \(T_C\) until it meets \(T_H\) at \(400\,\text{K}\). The work shrinks to nothing. The blue part never vanishes while the sink is warmer than absolute zero.

ExampleThe engine of a motorcycle

A motorcycle engine delivers \(7.5\,\text{kW}\) while burning petrol at \(2.4\,\text{kg}\) per hour. Burning \(1\,\text{kg}\) of petrol gives \(45\,\text{MJ}\) of heat. Find the efficiency of the engine and the rate at which it rejects heat.

Try it on paper first. The solution is one tap away when you are ready.
Checkpoint · numericUnanswered

An engine rejects \(75\,\%\) of the heat it takes in. What is its efficiency, as a percentage?

%± 2 %
Checkpoint · numericUnanswered

An engine takes \(50\,\text{kcal}\) from its source in each cycle and has an efficiency of \(20\,\%\). How much heat does it give to the sink in each cycle, in kJ? Take \(1\,\text{cal} = 4.2\,\text{J}\).

kJ± 2 %
Real engines and the water turbine

Real heat engines

A petrol engine takes a fresh charge of working substance in every cycle, a mixture of air and petrol vapour. The piston draws the mixture in and squeezes it. A spark burns it, and the hot gas pushes the piston out: this is the stroke that does the work. Then the piston pushes the used gas out through the exhaust. The hot exhaust carries away the rejected heat \(Q_C\), so the sink is the open air.

A coal power station keeps the same water in a closed loop. The furnace boils it to steam at a high pressure, and the steam spins a turbine. The spent steam must then be cooled back to water in a condenser before a pump returns it to the boiler. The condenser is the sink. Its heat goes into cooling water, and the cooling towers pass that heat to the air.

The best coal stations in India, such as Vindhyachal, turn about \(35\,\%\) of the heat of their coal into electricity. So a \(500\,\text{MW}\) unit must take in \(500/0.35 = 1429\,\text{MW}\) of heat. It rejects about \(929\,\text{MW}\). If all that heat went into evaporating water in the towers, about \(410\,\text{kg}\) of water would leave as vapour every second.

A coal station and a water turbineTwo energy-flow diagrams side by side. Left, a coal power station: 1000 joules of heat from the furnace enter the engine, 350 joules come out as work and 650 joules go as heat into river water; a heat engine, 35 percent. Right, the Bhakra turbine hall: 1000 joules of mechanical energy of water falling from the lake behind the dam enter the turbine, 900 joules come out as work and only 100 joules are lost to friction and eddies; not a heat engine, 90 percent.coal power station furnace 1000 J engine 350 J 650 J river water a heat engine: 35 % Bhakra turbine hall 1000 J turbine 900 J 100 J friction and eddies not a heat engine: 90 %
Fig 1.1Where \(1000\,\text{J}\) goes in two power stations. A coal station, a heat engine, turns \(350\,\text{J}\) into work and must give \(650\,\text{J}\) to the river. The turbines at Bhakra take mechanical energy from falling water, not heat, and lose only about \(100\,\text{J}\) to friction.

Now compare the turbine hall of the Bhakra dam on the Sutlej. Its turbines turn about \(90\,\%\) of the energy of the falling water into electricity. Is it a far better engine? No. It is not a heat engine at all. The water brings mechanical energy, which can in principle become work completely. Only friction and swirling water waste a little, as Fig 1.1 shows.

Common mistake

Do not compare a heat engine with a water turbine, an electric motor or a bicycle and call the heat engine "badly made". Those machines turn one form of work into another, and only friction limits them. A heat engine turns heat into work, and Lesson 2 shows that nature itself forbids it to turn all the heat into work.

CheckpointUnanswered

The Bhakra turbines convert about \(90\,\%\) of the water's energy into electricity, while a coal station converts about \(35\,\%\) of the coal's heat. Why is the gap so large?

Checkpoint · tap in orderUnanswered

Rank these by the fraction of their input energy that becomes useful work, largest first.

Now return to the cooling towers. The station takes in heat at the furnace and must give a large part of it to a cold sink. The towers are that sink at work. Lesson 2 shows that no design can remove them. A heat engine that gives no heat to a sink cannot exist.

Story · Thomas Newcomen, 1712
An engine that drank coal

In 1712 the English ironmonger Thomas Newcomen built a steam engine to pump water out of a coal mine. Steam filled a large cylinder, and a spray of cold water condensed it. The air outside then pushed the piston down. The engine worked, but it turned less than one percent of the heat of its coal into work. Every later engine, from James Watt's to the turbines of today, is a hunt for a larger share.

Exam traps
  1. Writing \(\eta = W/Q_C\) or \(\eta = Q_C/Q_H\).
    Efficiency divides the work by the heat taken in: \(\eta = W/Q_H = 1 - Q_C/Q_H\).
  2. Thinking that the working substance gains internal energy over a cycle.
    It returns to its starting state, so \(\Delta U = 0\) and the net heat equals the net work.
  3. Treating a water turbine or an electric motor as a heat engine.
    Only a device that turns heat into work in a cycle is a heat engine. Its limit is set by the second law, not by friction alone.