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The Second Law of Thermodynamics

13 min read4 ideas5 checks2 figures to playBy Asheshanand Acharya
What you will learn 0 / 4
Kelvin planck statement
Look around
The chai that never warms again

A glass of hot chai left on the table cools until it is as warm as the room. Nobody has ever seen a glass of chai at room temperature grow hot by itself while the room around it cools a little. Energy would be conserved in both cases. Yet only one of them ever happens.

you will meet the law that decides which way heat flows and which way a film may run, where the first law is silent.

What the first law does not forbid

The first law says that energy is conserved. It does not say which way a process runs. A block sliding on a rough floor stops, and its kinetic energy becomes heat in the block and the floor. The reverse would also conserve energy: a warm block and floor could cool and push the block into motion. The first law allows both films.

In the same way, the first law would allow an engine with \(Q_C = 0\). It would take heat from the sea and turn every joule into work. Cooling one cubic kilometre of sea water by \(1\,\text{K}\) releases \(4.2 \times 10^{15}\,\text{J}\), with \(c_\text{water} = 4200\,\text{J/(kg K)}\). That would run a \(1000\,\text{MW}\) power station for about \(49\) days, with no fuel. No such engine has ever worked.

The failure of every such attempt is itself a law of nature. It is the second law of thermodynamics, and it has two classic forms. The first form, due to Kelvin and Planck, is about engines.

law 5.1
The second law: Kelvin-Planck statement

No engine working in a cycle can take heat from a single reservoir and turn all of it into work. Some heat must always be given to a colder reservoir.

The words "in a cycle" matter. A gas expanding at constant temperature does turn all the heat it takes into work, as the chapter on the First Law showed. But it ends with a larger volume and a lower pressure, so it cannot repeat the stroke without being compressed. Bringing it back costs work and rejects heat. The statement forbids only the perfect engine that runs for ever.

A machine that would break this law is a perpetual motion machine of the second kind. It breaks no energy law, since it only turns heat into an equal amount of work. It fails because it has no sink. So the Kelvin-Planck statement is often put in one line: the efficiency of a heat engine is always less than \(1\).

CheckpointUnanswered

An inventor proposes a ship that takes in warm sea water and extracts heat from it to drive the propeller. The cooled water, now ice, is dropped overboard. No fuel is burnt. What is wrong with it?

Clausius statement

Heat flows downhill

The second form of the law, due to Clausius, is about the direction of heat flow. Heat flows by itself from a hot body to a cold one, as in the cooling chai. The reverse never happens on its own.

law 5.2
The second law: Clausius statement

No device working in a cycle can move heat from a colder body to a hotter body with no other effect. Heat does not flow from cold to hot by itself.

A refrigerator does move heat from its cold inside to the warmer kitchen. It does not break the law, because it has another effect. Its motor takes electrical work from the mains, and the kitchen receives that work as extra heat. The law forbids only a transfer from cold to hot that happens with nothing else changing.

CheckpointUnanswered

A refrigerator takes \(300\,\text{J}\) of heat from its inside and gives \(400\,\text{J}\) to the kitchen in the same time. Why does it not break the Clausius statement?

The two statements agree

Two statements, one law

The two statements look different: one is about engines, the other about heat flow. In fact each one implies the other. If either could be broken, so could the other. Fig 2.1 shows one half of the proof with numbers.

A perfect refrigerator would make a perfect engineA hot source above and a cold sink below. Chip one: an ordinary engine takes 1000 joules from the hot source, does 400 joules of work and rejects 600 joules to the cold sink. Chip two: a perfect refrigerator, which needs no work, is added beside it and carries the 600 joules from the cold sink back up to the hot source. Chip three: a box is drawn round the two devices as one machine. The cold sink gains nothing and loses nothing. The hot source loses 400 joules net, and the machine turns all 400 joules into work, which the Kelvin-Planck statement forbids.hot source, TH cold sink, TC engine 1000 J 400 J 600 J fridge 600 J 600 J engine: W = 400 J, QC = 600 J
Fig 2.1An ordinary engine takes \(1000\,\text{J}\) from the source, does \(400\,\text{J}\) of work and rejects \(600\,\text{J}\). Add a perfect refrigerator that carries the \(600\,\text{J}\) back up with no work. Take the chips in order and look at the two devices as one machine.

Suppose a perfect refrigerator existed, one that breaks the Clausius statement. Join it to an ordinary engine as in Fig 2.1. The cold sink receives \(600\,\text{J}\) from the engine and loses \(600\,\text{J}\) to the refrigerator, so nothing changes there. The hot source gives \(1000\,\text{J}\) and gets \(600\,\text{J}\) back, a net \(400\,\text{J}\). The combined machine turns that \(400\,\text{J}\) wholly into work.

That combined machine is a perfect engine, forbidden by the Kelvin-Planck statement. So a perfect refrigerator cannot exist either. The other half runs the same way. A perfect engine could take \(300\,\text{J}\) from the source and turn it into \(300\,\text{J}\) of work. That work could drive an ordinary refrigerator that moves \(900\,\text{J}\) from the cold body and gives \(1200\,\text{J}\) to the hot one.

Count the heat of the hot body in that second machine. It gives \(300\,\text{J}\) to the perfect engine and receives \(1200\,\text{J}\) from the refrigerator. Net, \(900\,\text{J}\) has moved from the cold body to the hot body, and no work came from outside. That breaks the Clausius statement. So each statement guards the other.

Checkpoint · select all that applyUnanswered

Which statements about the two forms of the second law are true?

Reversible and irreversible processes
A film of friction, forwards and backwardsA 1 kilogram block slides at 4 metres per second on a rough floor with a small thermometer standing on it. Chip forwards: friction slows it to rest in 2 seconds over 4 metres; its kinetic energy falls from 8 joules to zero while the heat in the block and the floor rises from zero to 8 joules, and the thermometer creeps up. Chip backwards: the same film reversed. The warm block at rest cools, the thermometer falls, and the block starts to move and speeds up to 4 metres per second. Energy is conserved in both films, but only the first ever happens. v K = 8.0 J, heat = 0.0 J
Fig 2.2A \(1\,\text{kg}\) block slides at \(4\,\text{m/s}\) on a floor with \(\mu_k = 0.2\), taking \(g = 10\,\text{m/s}^2\). It stops in \(2\,\text{s}\) after \(4\,\text{m}\), and \(8\,\text{J}\) of kinetic energy becomes heat. Play the film forwards, then backwards. (The thermometer is only a sign of warming: \(8\,\text{J}\) warms the block by a small fraction of a kelvin.)

Both films in Fig 2.2 keep the total energy at \(8\,\text{J}\). But only the forward film is ever seen. The backward film needs the random jiggling of the molecules in a warm block to line up and push the whole block the same way. That never happens. The sliding stop is an irreversible process.

A reversible process is one that can be run backwards so that the system and everything around it return exactly to their first states. A process is reversible only if it is quasi-static, so that each stage is an equilibrium state. It must also have no friction, and heat may flow only across a vanishingly small temperature difference.

Three things make a process irreversible. Friction turns ordered motion into heat. A free expansion lets a gas rush into a vacuum, and the gas never gathers back into its corner by itself. Heat flowing across a finite difference of temperature, as from hot chai to the room, never flows back. Every real process has at least one of these.

Intuition

A reversible process is like an ideal slope with no friction. It is never quite reached, yet it is useful, because real processes can come as close to it as we please. Squeeze a gas very slowly with a well-oiled piston, touching a reservoir only a hair warmer or colder than the gas. The process is then almost reversible.

Property
Reversible
Irreversible
Speed
quasi-static, infinitely slow
finite speed, as every real process
Heat flow
across a vanishingly small temperature difference
across a finite temperature difference
Friction
none
present, turning work into heat
Run backwards
system and surroundings both return exactly
cannot be undone without a change left somewhere
Example
a gas squeezed very slowly with a frictionless piston
a block sliding to rest, a gas rushing into a vacuum
CheckpointUnanswered

Which of these processes comes closest to being reversible?

Checkpoint · in your own wordsUnanswered

Energy is conserved both when a warm block and floor cool while the block starts to slide, and when a sliding block stops and warms. Explain why only the second is ever seen.

Now return to the glass of chai. The first law cannot decide between a cooling glass and a warming one. The second law does. Heat flows by itself only from hot to cold, so the chai cools and never warms again. The next lesson finds how close a real engine can come to the ideal, reversible limit.

Story · Rudolf Clausius and William Thomson (Lord Kelvin), 1850
Two statements of one law

In 1850 the German physicist Rudolf Clausius showed that Carnot's ideas survive if heat never passes by itself from cold to hot. A year later in Glasgow, William Thomson, later Lord Kelvin, wrote a second form. No engine can draw work from a body by cooling it below its coldest surroundings. Both men were trying to reconcile Carnot's engine with the new idea that heat is energy. Together their papers founded the second law.

In the world
Power from a warm sea, done properly

A plant for ocean thermal energy conversion uses the warm surface of a tropical sea as its source. Its sink is cold water pumped up from hundreds of metres below. Such a plant obeys the second law because it has two reservoirs. With only about \(20\,\text{K}\) between them, its efficiency is only a few percent. In Lakshadweep, plants of the National Institute of Ocean Technology use the same warm and cold water to make fresh water from the sea.

Exam traps
  1. Thinking that a refrigerator breaks the second law.
    The Clausius statement forbids moving heat from cold to hot with no other effect. A refrigerator uses work.
  2. Believing that an isothermal expansion breaks the Kelvin-Planck statement.
    The statement is about a cycle. A single expansion does not repeat; bringing the gas back rejects heat.
  3. Calling any slow process reversible.
    It must also be free of friction, and heat may cross only a tiny temperature difference.