Magnetisation
Put a rod of some material inside a long solenoid and pass a current. The atoms of the rod carry tiny magnetic moments, and the field of the solenoid lines some of them up, or makes new ones. The rod becomes magnetised. Its magnetisation is its net magnetic moment per unit volume. A moment in A m² divided by a volume in m³ gives the unit A/m.
In this lesson \(M\) stands for the magnetisation, in A/m, as in most books. In Lessons 1 to 4 it was the moment of a magnet, in A m². The two are linked: a uniformly magnetised bar of volume \(V\) has a moment equal to its magnetisation times \(V\).
The field inside the rod now has two sources. One is the current in the solenoid, which is called a free current because it flows in wires we control. The other is the lined-up atoms, which act like a current round the surface of the rod, as in Lesson 1. The first source alone sets the magnetic intensity \(\vec H\). In a long solenoid \(H = nI\), whatever the core, where \(n\) is the number of turns per metre.
The magnetic intensity is \(\vec H = \vec B/\mu_0 - \vec M\), where \(\vec M\) is the magnetisation. It is the part of the field set by the free currents alone, and it is measured in A/m.
So \(\vec B = \mu_0(\vec H + \vec M)\). In most materials the magnetisation grows in proportion to \(H\). The ratio is the susceptibility, \(\chi = M/H\), a pure number. Then \(B = \mu_0(1 + \chi)H\). The number \(\mu_r = 1 + \chi\) is the relative permeability, and \(\mu = \mu_0\mu_r\) is the permeability of the material.
(a) A paramagnetic rod with \(\chi = 3 \times 10^{-4}\) is placed in \(H = 10^4\,\text{A/m}\). Find its magnetisation and the field inside it. (b) A long solenoid has \(1000\) turns per metre and carries \(2\,\text{A}\). Find \(B\) inside it with an air core, and with a soft-iron core of \(\mu_r = 500\).
(a) \(M = \chi H = 3 \times 10^{-4} \times 10^4 = 3\,\text{A/m}\). \(B\) \(= \mu_0(H + M)\) \(= 4\pi \times 10^{-7} \times 10\,003\) \(= 1.26 \times 10^{-2}\,\text{T}\). Without the rod it would be \(1.2566 \times 10^{-2}\,\text{T}\); the rod adds only \(0.03\%\).
(b) \(H = nI = 2000\,\text{A/m}\) with either core. Air: \(B = \mu_0 H = 2.51 \times 10^{-3}\,\text{T}\). Iron: \(B\) \(= \mu_0\mu_r H\) \(= 500 \times 2.51 \times 10^{-3}\) \(= 1.26\,\text{T}\). The iron's magnetisation is \((\mu_r - 1)H = 9.98 \times 10^5\,\text{A/m}\).
Values used: \(\mu_0 = 4\pi \times 10^{-7}\,\text{T m/A}\).
That is why the solenoid of an electromagnet, in the chapter Sources of the Magnetic Field, is wound on iron. The current sets the same \(H\) either way. The lined-up atoms of the iron multiply the field hundreds of times.
A rod with susceptibility \(1.5 \times 10^{-3}\) lies in a magnetic intensity of \(2000\,\text{A/m}\). Find its magnetisation, in A/m.
Three kinds of material
Every material falls into one of three groups by its susceptibility. A diamagnetic material has a small negative \(\chi\), about \(-10^{-5}\). Copper, water, gold and bismuth are diamagnetic. A paramagnetic material has a small positive \(\chi\), from about \(10^{-5}\) to \(10^{-3}\). Aluminium, with \(\chi\) about \(2 \times 10^{-5}\), platinum and oxygen are paramagnetic. A ferromagnetic material has a large positive \(\chi\), from hundreds to many thousands. Iron, nickel and cobalt are ferromagnetic.
Fig 5.1 shows the difference. A paramagnet draws field lines into itself, so the field inside is stronger than outside. A diamagnet pushes some lines out, so the field inside is weaker. Where a field is stronger on one side, a paramagnet is pulled towards the stronger region. A diamagnet is pushed towards the weaker one. A paramagnetic rod turns to lie along the field; a diamagnetic rod turns across it.
The causes differ. In a diamagnet the atoms have no moment of their own. The applied field slightly changes the orbits of the electrons, and the change opposes the field. The chapter Faraday's Law, Lenz's Law and Motional EMF explains why. Every material has this effect, but it is weak. In a paramagnet each atom has a moment. The field turns them partly into line, while the thermal jiggling of the atoms keeps knocking them out of line.
A ferromagnet is different in kind. Neighbouring atomic moments in iron hold one another parallel by a strong quantum effect. So iron is made of domains, small regions up to about a millimetre across, each already fully magnetised. In unmagnetised iron the domains point every way and cancel. A field makes the domains that point along it grow at the expense of the others, and then turns them. Even a small \(H\) therefore gives a huge \(M\).
A superconductor, cooled below its critical temperature, pushes the field out of itself completely. Inside it \(B = 0\), so \(M = -H\) and \(\chi = -1\): it is a perfect diamagnet. This is the Meissner effect, found in 1933. The superconductor chip of Fig 5.1 shows every line bending round the sphere. A small magnet placed above a cooled superconductor floats, held up by this repulsion.
A small rod hangs by a thread between the poles of a strong electromagnet, where the field is not uniform. It turns to lie along the field and is pulled towards the stronger region. What kind of material is it?
Arrange these in order of their magnetic susceptibility, from the smallest to the largest.
The door of the MRI room at AIIMS in New Delhi carries a warning: no steel trolleys, no oxygen cylinders, no hairpins. The magnet inside keeps a field of about \(1.5\,\text{T}\), some thirty thousand times the Earth's field at Delhi. Iron and steel are ferromagnetic. Near the magnet they are magnetised strongly and pulled towards the stronger field, fast enough to fly across the room. Aluminium and plastic trolleys are safe: aluminium is only feebly paramagnetic.
Heat against order
In a paramagnet the field lines up the atomic moments, and thermal jiggling knocks them out of line. The hotter the material, the harder the jiggling and the smaller the magnetisation for a given field. For a paramagnet the susceptibility is inversely proportional to the absolute temperature. This is Curie's law, found by Pierre Curie in 1895.
A paramagnetic salt with \(\chi = 2 \times 10^{-4}\) at \(300\,\text{K}\) has, at \(150\,\text{K}\), \(\chi\) \(= 2 \times 10^{-4} \times 300/150\) \(= 4 \times 10^{-4}\). Halving the absolute temperature doubles the susceptibility.
Heat also destroys ferromagnetism. Above a temperature called the Curie temperature, the jiggling breaks up the domains, and a ferromagnet becomes an ordinary paramagnet. For iron this is \(1043\,\text{K}\), or \(770\,°\text{C}\). For nickel it is about \(631\,\text{K}\) and for cobalt about \(1388\,\text{K}\). That is why the molten core of the Earth, thousands of kelvin hot, cannot be a permanent magnet.
Above its Curie temperature \(T_C\), a ferromagnet follows the Curie-Weiss law, \(\chi = C/(T - T_C)\). The susceptibility grows without limit as \(T\) falls towards \(T_C\), where the domains form again.
A paramagnetic salt has a susceptibility of \(3 \times 10^{-4}\) at \(250\,\text{K}\). Find its susceptibility at \(375\,\text{K}\), in units of \(10^{-4}\).
Before the work on radioactivity that made him famous, Pierre Curie studied how magnets behave when heated. For his doctoral thesis of 1895 he measured many substances over a wide range of temperatures. He found that a paramagnet's susceptibility falls in inverse proportion to the absolute temperature. He also found that iron loses its strong magnetism above a sharp temperature. Both results now carry his name.
A material that remembers
Take an unmagnetised iron rod in a solenoid and raise \(H\) slowly. \(B\) rises along a curve and levels off when nearly every domain lines up: the iron is saturated. Now lower \(H\) back to zero. The domains do not all return, so \(B\) stays well above zero. Reverse the current, and a reverse \(H\) is needed to bring \(B\) to zero. Carry on round, and \(B\) traces a closed loop. This lagging of \(B\) behind \(H\) is hysteresis.
The field left when \(H\) returns to zero is the retentivity, point R. The reverse intensity needed to bring \(B\) to zero is the coercivity, point C. In Fig 5.2 both materials keep about \(1.25\,\text{T}\) at R. Soft iron needs only \(0.5\,\text{kA/m}\) to clear it, while steel needs \(3\,\text{kA/m}\). The steel loop is fat and the soft-iron loop thin.
Going round the loop costs energy. Each cycle drags the domain walls to and fro, and the work done turns into heat in the material. The area enclosed by the loop on a \(B\)-\(H\) graph is the energy lost per cycle in each cubic metre. Its unit, tesla times A/m, is J/m³. In Fig 5.2 the steel loop has about five times the area of the soft-iron loop.
The iron core of a transformer has a volume of \(2 \times 10^{-3}\,\text{m}^3\). Its hysteresis loop encloses \(60\,\text{J/m}^3\), and the mains takes it round the loop \(50\) times a second. Find the power lost as heat.
Energy per cycle \(= 60 \times 2 \times 10^{-3} = 0.12\,\text{J}\).
Power \(= 0.12 \times 50 = 6\,\text{W}\), every second the transformer is on. A core with a fatter loop would waste more, which is why transformer cores are made of soft iron.
A material's loop decides its use. An electromagnet, a transformer core or the core of a galvanometer must magnetise easily and let go cleanly. So it needs soft iron: high permeability, low retentivity and low coercivity, a thin loop that wastes little energy. A permanent magnet must keep its magnetism against knocks and stray fields. So it needs a material like steel: high retentivity and high coercivity, a fat loop.
Which properties make soft iron the right core for a transformer? Choose all that apply.
A core of volume \(5 \times 10^{-3}\,\text{m}^3\) has a hysteresis loop of area \(150\,\text{J/m}^3\). It is taken round the loop \(50\) times a second. Find the power lost as heat, in watts.
- Using \(M\) for the moment of a magnet in a problem on materials.Here \(M\) is the magnetisation, moment per unit volume, in A/m.
- Giving a diamagnet a small positive susceptibility.Diamagnets have a negative \(\chi\); they are pushed towards the weaker field.
- Using degrees Celsius in Curie's law.\(\chi = C/T\) needs the absolute temperature in kelvin.
- Choosing steel for a transformer core because it is a strong magnet.A core cycles 50 times a second. It needs the thin loop of soft iron, not the fat loop of steel.