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Magnetism and Matter · Lesson 5 of 5

Magnetic Materials

15 min read4 ideas6 checks2 figures to playBy Asheshanand Acharya
What you will learn 0 / 4
Magnetisation intensity and susceptibility

Magnetisation

Put a rod of some material inside a long solenoid and pass a current. The atoms of the rod carry tiny magnetic moments, and the field of the solenoid lines some of them up, or makes new ones. The rod becomes magnetised. Its magnetisation is its net magnetic moment per unit volume. A moment in A m² divided by a volume in m³ gives the unit A/m.

Common mistake

In this lesson \(M\) stands for the magnetisation, in A/m, as in most books. In Lessons 1 to 4 it was the moment of a magnet, in A m². The two are linked: a uniformly magnetised bar of volume \(V\) has a moment equal to its magnetisation times \(V\).

The field inside the rod now has two sources. One is the current in the solenoid, which is called a free current because it flows in wires we control. The other is the lined-up atoms, which act like a current round the surface of the rod, as in Lesson 1. The first source alone sets the magnetic intensity \(\vec H\). In a long solenoid \(H = nI\), whatever the core, where \(n\) is the number of turns per metre.

definition 12.2
Magnetic intensity

The magnetic intensity is \(\vec H = \vec B/\mu_0 - \vec M\), where \(\vec M\) is the magnetisation. It is the part of the field set by the free currents alone, and it is measured in A/m.

So \(\vec B = \mu_0(\vec H + \vec M)\). In most materials the magnetisation grows in proportion to \(H\). The ratio is the susceptibility, \(\chi = M/H\), a pure number. Then \(B = \mu_0(1 + \chi)H\). The number \(\mu_r = 1 + \chi\) is the relative permeability, and \(\mu = \mu_0\mu_r\) is the permeability of the material.

RememberField, intensity and magnetisation
\[ \vec B = \mu_0(\vec H + \vec M) \]
Holds wheninside any material; \(\vec H\) is set by the free currents and \(\vec M\) is the magnetisation.
Symbols\(B\) magnetic field, \(H\) magnetic intensity, \(M\) magnetisation
Units\(B\) in T, \(H\) and \(M\) in A/m
RememberSusceptibility
\[ \chi = \dfrac{M}{H} \]
Holds whena material whose magnetisation is proportional to \(H\): every diamagnet and paramagnet, and a ferromagnet only roughly, over a small range.
Symbols\(\chi\) susceptibility, a pure number; \(M\) magnetisation; \(H\) magnetic intensity
Units\(M\) and \(H\) in A/m
RememberRelative permeability
\[ \mu_r = 1 + \chi \]
Holds whenthe same materials; then \(B = \mu_0\mu_r H\).
Symbols\(\mu_r\) relative permeability, \(\chi\) susceptibility
Unitsboth pure numbers
ExampleA paramagnetic rod and an iron core

(a) A paramagnetic rod with \(\chi = 3 \times 10^{-4}\) is placed in \(H = 10^4\,\text{A/m}\). Find its magnetisation and the field inside it. (b) A long solenoid has \(1000\) turns per metre and carries \(2\,\text{A}\). Find \(B\) inside it with an air core, and with a soft-iron core of \(\mu_r = 500\).

Try it on paper first. The solution is one tap away when you are ready.

That is why the solenoid of an electromagnet, in the chapter Sources of the Magnetic Field, is wound on iron. The current sets the same \(H\) either way. The lined-up atoms of the iron multiply the field hundreds of times.

Checkpoint · numericUnanswered

A rod with susceptibility \(1.5 \times 10^{-3}\) lies in a magnetic intensity of \(2000\,\text{A/m}\). Find its magnetisation, in A/m.

A/m± 2 %
Dia para and ferromagnetism

Three kinds of material

Every material falls into one of three groups by its susceptibility. A diamagnetic material has a small negative \(\chi\), about \(-10^{-5}\). Copper, water, gold and bismuth are diamagnetic. A paramagnetic material has a small positive \(\chi\), from about \(10^{-5}\) to \(10^{-3}\). Aluminium, with \(\chi\) about \(2 \times 10^{-5}\), platinum and oxygen are paramagnetic. A ferromagnetic material has a large positive \(\chi\), from hundreds to many thousands. Iron, nickel and cobalt are ferromagnetic.

A sphere of material in a uniform fieldA sphere placed in a uniform magnetic field that runs to the right, with the field lines traced through and around it. A paramagnet draws the lines in, so the field inside is stronger than outside. A diamagnet pushes them out, so the field inside is weaker. A superconductor expels the field completely, and the lines flow round it. The susceptibilities are exaggerated tens of thousands of times for the first two, so the bending can be seen. μr = 4, exaggerated: Bin/B0 = 2.0
Fig 5.1A sphere of material in a uniform field that runs to the right, with the field lines traced through it. The susceptibilities are exaggerated tens of thousands of times for the first two chips, so the bending can be seen. Compare how many lines pass through the sphere in each case.

Fig 5.1 shows the difference. A paramagnet draws field lines into itself, so the field inside is stronger than outside. A diamagnet pushes some lines out, so the field inside is weaker. Where a field is stronger on one side, a paramagnet is pulled towards the stronger region. A diamagnet is pushed towards the weaker one. A paramagnetic rod turns to lie along the field; a diamagnetic rod turns across it.

The causes differ. In a diamagnet the atoms have no moment of their own. The applied field slightly changes the orbits of the electrons, and the change opposes the field. The chapter Faraday's Law, Lenz's Law and Motional EMF explains why. Every material has this effect, but it is weak. In a paramagnet each atom has a moment. The field turns them partly into line, while the thermal jiggling of the atoms keeps knocking them out of line.

A ferromagnet is different in kind. Neighbouring atomic moments in iron hold one another parallel by a strong quantum effect. So iron is made of domains, small regions up to about a millimetre across, each already fully magnetised. In unmagnetised iron the domains point every way and cancel. A field makes the domains that point along it grow at the expense of the others, and then turns them. Even a small \(H\) therefore gives a huge \(M\).

Property
Diamagnetic
Paramagnetic
Susceptibility \(\chi\)
small and negative, about \(-10^{-5}\)
small and positive, \(10^{-5}\) to \(10^{-3}\)
Relative permeability
a little less than 1
a little more than 1
In a non-uniform field
moves towards the weaker field
moves towards the stronger field
A rod in a uniform field
turns across the field
turns along the field
Effect of temperature
almost none
\(\chi\) falls as \(1/T\)
Examples
bismuth, copper, water, gold
aluminium, platinum, oxygen
Deeper

A superconductor, cooled below its critical temperature, pushes the field out of itself completely. Inside it \(B = 0\), so \(M = -H\) and \(\chi = -1\): it is a perfect diamagnet. This is the Meissner effect, found in 1933. The superconductor chip of Fig 5.1 shows every line bending round the sphere. A small magnet placed above a cooled superconductor floats, held up by this repulsion.

CheckpointUnanswered

A small rod hangs by a thread between the poles of a strong electromagnet, where the field is not uniform. It turns to lie along the field and is pulled towards the stronger region. What kind of material is it?

Checkpoint · tap in orderUnanswered

Arrange these in order of their magnetic susceptibility, from the smallest to the largest.

In the world
The sign on the MRI door at AIIMS

The door of the MRI room at AIIMS in New Delhi carries a warning: no steel trolleys, no oxygen cylinders, no hairpins. The magnet inside keeps a field of about \(1.5\,\text{T}\), some thirty thousand times the Earth's field at Delhi. Iron and steel are ferromagnetic. Near the magnet they are magnetised strongly and pulled towards the stronger field, fast enough to fly across the room. Aluminium and plastic trolleys are safe: aluminium is only feebly paramagnetic.

Curies law

Heat against order

In a paramagnet the field lines up the atomic moments, and thermal jiggling knocks them out of line. The hotter the material, the harder the jiggling and the smaller the magnetisation for a given field. For a paramagnet the susceptibility is inversely proportional to the absolute temperature. This is Curie's law, found by Pierre Curie in 1895.

RememberCurie's law
\[ \chi = \dfrac{C}{T} \]
Holds whena paramagnet, not too cold and in a field not too strong; \(T\) is the absolute temperature.
Symbols\(\chi\) susceptibility, \(C\) Curie constant of the material, \(T\) temperature
Units\(T\) in K, \(C\) in K

A paramagnetic salt with \(\chi = 2 \times 10^{-4}\) at \(300\,\text{K}\) has, at \(150\,\text{K}\), \(\chi\) \(= 2 \times 10^{-4} \times 300/150\) \(= 4 \times 10^{-4}\). Halving the absolute temperature doubles the susceptibility.

Heat also destroys ferromagnetism. Above a temperature called the Curie temperature, the jiggling breaks up the domains, and a ferromagnet becomes an ordinary paramagnet. For iron this is \(1043\,\text{K}\), or \(770\,°\text{C}\). For nickel it is about \(631\,\text{K}\) and for cobalt about \(1388\,\text{K}\). That is why the molten core of the Earth, thousands of kelvin hot, cannot be a permanent magnet.

Deeper

Above its Curie temperature \(T_C\), a ferromagnet follows the Curie-Weiss law, \(\chi = C/(T - T_C)\). The susceptibility grows without limit as \(T\) falls towards \(T_C\), where the domains form again.

Checkpoint · numericUnanswered

A paramagnetic salt has a susceptibility of \(3 \times 10^{-4}\) at \(250\,\text{K}\). Find its susceptibility at \(375\,\text{K}\), in units of \(10^{-4}\).

× 10⁻⁴± 2 %
Story · Pierre Curie, 1895
A thesis on heat and magnetism

Before the work on radioactivity that made him famous, Pierre Curie studied how magnets behave when heated. For his doctoral thesis of 1895 he measured many substances over a wide range of temperatures. He found that a paramagnet's susceptibility falls in inverse proportion to the absolute temperature. He also found that iron loses its strong magnetism above a sharp temperature. Both results now carry his name.

Hysteresis retentivity and coercivity

A material that remembers

Take an unmagnetised iron rod in a solenoid and raise \(H\) slowly. \(B\) rises along a curve and levels off when nearly every domain lines up: the iron is saturated. Now lower \(H\) back to zero. The domains do not all return, so \(B\) stays well above zero. Reverse the current, and a reverse \(H\) is needed to bring \(B\) to zero. Carry on round, and \(B\) traces a closed loop. This lagging of \(B\) behind \(H\) is hysteresis.

The hysteresis loopThe magnetic field B inside a sample of iron or steel against the magnetising field H. H rises from zero to 9 kiloamperes per metre along the first magnetisation curve, falls to minus 9 and rises again to plus 9, and the point traces a closed loop. When H returns to zero some field remains: the retentivity R. A reverse H is needed to bring B to zero: the coercivity C. Soft iron has a tall, thin loop; steel has a fat loop, with a coercivity six times larger and about five times the area. The area is the energy lost as heat per cycle in each cubic metre. The soft-iron loop is drawn wider than a real one, which would look like a single line.369−3−6−90.511.5−0.5−1−1.5OH (kA/m)B (T) R C soft iron: Br = 1.25 T, Hc = 0.50 kA/m
Fig 5.2Press play. \(H\) rises from zero to \(9\,\text{kA/m}\) along the dashed first curve, then falls to \(-9\) and rises again. R marks the retentivity, the field left at \(H = 0\); C marks the coercivity, the reverse \(H\) that brings \(B\) to zero. Switch between soft iron and steel. The numbers are typical sizes, rounded, and the soft-iron loop is drawn wider than a real one.

The field left when \(H\) returns to zero is the retentivity, point R. The reverse intensity needed to bring \(B\) to zero is the coercivity, point C. In Fig 5.2 both materials keep about \(1.25\,\text{T}\) at R. Soft iron needs only \(0.5\,\text{kA/m}\) to clear it, while steel needs \(3\,\text{kA/m}\). The steel loop is fat and the soft-iron loop thin.

Going round the loop costs energy. Each cycle drags the domain walls to and fro, and the work done turns into heat in the material. The area enclosed by the loop on a \(B\)-\(H\) graph is the energy lost per cycle in each cubic metre. Its unit, tesla times A/m, is J/m³. In Fig 5.2 the steel loop has about five times the area of the soft-iron loop.

ExampleHeat in a transformer core

The iron core of a transformer has a volume of \(2 \times 10^{-3}\,\text{m}^3\). Its hysteresis loop encloses \(60\,\text{J/m}^3\), and the mains takes it round the loop \(50\) times a second. Find the power lost as heat.

Try it on paper first. The solution is one tap away when you are ready.

A material's loop decides its use. An electromagnet, a transformer core or the core of a galvanometer must magnetise easily and let go cleanly. So it needs soft iron: high permeability, low retentivity and low coercivity, a thin loop that wastes little energy. A permanent magnet must keep its magnetism against knocks and stray fields. So it needs a material like steel: high retentivity and high coercivity, a fat loop.

Checkpoint · select all that applyUnanswered

Which properties make soft iron the right core for a transformer? Choose all that apply.

Checkpoint · numericUnanswered

A core of volume \(5 \times 10^{-3}\,\text{m}^3\) has a hysteresis loop of area \(150\,\text{J/m}^3\). It is taken round the loop \(50\) times a second. Find the power lost as heat, in watts.

W± 2 %
Exam traps
  1. Using \(M\) for the moment of a magnet in a problem on materials.
    Here \(M\) is the magnetisation, moment per unit volume, in A/m.
  2. Giving a diamagnet a small positive susceptibility.
    Diamagnets have a negative \(\chi\); they are pushed towards the weaker field.
  3. Using degrees Celsius in Curie's law.
    \(\chi = C/T\) needs the absolute temperature in kelvin.
  4. Choosing steel for a transformer core because it is a strong magnet.
    A core cycles 50 times a second. It needs the thin loop of soft iron, not the fat loop of steel.