A grating made by nature
To measure the wavelength of light, one uses a grating of fine lines ruled close together. Its lines must be about as far apart as the wavelength. X-rays have wavelengths near \(0.1\,\text{nm}\), the size of an atom. No ruling machine can space lines so finely. In 1912 Max von Laue saw that nature had already made such a grating: a crystal.
In a crystal of rock salt, sodium and chlorine atoms stand in a pattern that repeats in every direction. Through such a pattern one can draw many sets of parallel crystal planes, each full of atoms. The planes of one set are a fixed distance \(d\) apart. In rock salt, one important set has \(d = 0.282\,\text{nm}\).
Each plane of atoms acts like a very weak mirror. It sends back a tiny fraction of an X-ray beam, and lets the rest go on to the next plane. The reflected ray leaves at the same angle to the plane as the incoming ray. For X-rays the angle is measured from the plane itself. It is called the glancing angle \(\theta\).
A single plane reflects too little to notice. But a beam enters millions of planes, and every one of them reflects a little. Whether these small reflections add up depends on their paths. If they arrive in step, they reinforce into a strong beam. If not, they cancel, as two waves on a string do, and as light does in the chapter on interference.
The extra path
Look again at Fig 5.1. Ray 2 goes deeper than ray 1, by one plane. Drop a perpendicular from A onto ray 2 before it reflects, and another after it reflects. Up to the first perpendicular the two rays have gone equal distances, and after the second they go on side by side. The difference lies in the two thick pieces, CB and BD.
\[ AB = d \]
Why. B is on the next plane, straight below A.
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Your turn. in the right triangle ACB the angle at A equals \(\theta\), and AB is the hypotenuse. Which line is it?
\[ BD = d\sin\theta \]
Why. the outgoing ray makes the same angle \(\theta\) with the plane, so the triangle ADB is a mirror copy of ACB.
\[ CB + BD = 2d\sin\theta \]
Read it. add the two pieces; this is the extra path of ray 2.
The two rays reinforce when this extra path is a whole number of wavelengths. Then the crests of ray 2 fall on the crests of ray 1, and the same holds for every deeper plane. This is the condition found by William Lawrence Bragg in 1912, Bragg's law.
X-rays of wavelength \(\lambda\) reflected from a set of parallel crystal planes a distance \(d\) apart give a strong beam only when \(2d\sin\theta = n\lambda\). Here \(\theta\) is the glancing angle and \(n = 1, 2, 3, \ldots\) is the order of reflection.
Turn the angle slowly in the figure above. At most angles the extra path is some odd fraction of a wavelength, and the two waves partly cancel. With millions of planes, each a little further out of step, the reflections cancel almost completely. Only near \(15.8°\), \(33.1°\) and \(55.0°\) do all the planes agree, and the crystal sends back a strong beam.
How many orders?
The sine of an angle is never more than one. So \(n\lambda = 2d\sin\theta\) can be at most \(2d\). The orders that exist are the whole numbers \(n \le 2d/\lambda\). For copper Kα on rock salt, \(2d/\lambda = 0.564/0.154 = 3.66\), so there are three orders. A wave longer than \(2d\) gives no strong reflection at all.
X-rays of wavelength \(1.0\,\text{Å}\) fall on a crystal whose planes are \(2.0\,\text{Å}\) apart. Find the glancing angles of the first-order and second-order maxima. What is the highest order that can occur?
\(\lambda = 1.0\,\text{Å}\) and \(d = 2.0\,\text{Å}\), so \(2d = 4.0\,\text{Å}\).
\(\sin\theta = n\lambda/2d = n \times 1.0/4.0 = 0.25\,n\).
\(n = 1\): \(\sin\theta = 0.25\), \(\theta = 14.5°\). \(n = 2\): \(\sin\theta = 0.50\), \(\theta = 30°\). \(n = 3\): \(\theta = 48.6°\).
\(\sin\theta \le 1\) needs \(0.25\,n \le 1\), so \(n \le 4\). The fourth order needs \(\theta = 90°\), the beam along the normal of the planes and reflected straight back: the limit, not an easy angle to observe. Values used: none beyond the data.
The glancing angle is measured from the plane, not from the normal. A beam that meets the planes at \(60°\) to their normal has \(\theta = 30°\). The reflected beam is then turned through \(2\theta\) from its first direction, which is why a Bragg detector sits at \(2\theta\) from the beam.
X-rays strike a set of crystal planes at \(70°\) to the normal of the planes. What value of \(\theta\) goes into Bragg's law?
The first-order maximum for X-rays of \(0.154\,\text{nm}\) from a set of planes is at a glancing angle of \(30°\). Find the spacing \(d\) of the planes, in nm.
The Bragg spectrometer
The Braggs, father and son, built an instrument to use the law. A narrow X-ray beam falls on a crystal mounted on a turntable. As the crystal turns through the glancing angle \(\theta\), a detector turns through \(2\theta\). So the detector always stands where a reflection would go. A graph of the count against \(\theta\) shows a sharp peak at every Bragg angle.
Check the three peaks in the figure above against Bragg's law. Their sines are \(0.273\), \(0.546\) and \(0.819\), in the ratio \(1 : 2 : 3\). That ratio tells the experimenter that the peaks are orders 1, 2 and 3 of one wavelength. The first gives \(\lambda = 2d\sin\theta = 0.564 \times 0.273 = 0.154\,\text{nm}\).
The spectrometer works in two directions. With X-rays of a known wavelength, the angles give the spacing \(d\) of a crystal's planes, and so the arrangement of its atoms. With a crystal of known \(d\), the angles give the wavelength of unknown X-rays. Moseley measured his Kα lines this way, with crystals of known spacing.
(a) Rock-salt planes are \(2.82\,\text{Å}\) apart. Find the first-order glancing angle for X-rays of \(1.41\,\text{Å}\). (b) A crystal with \(d = 1.0\,\text{Å}\) gives a first-order maximum at \(30°\). Find the wavelength, and the least tube voltage that can make it.
(a) \(\sin\theta = \lambda/2d = 1.41/5.64 = 0.25\), so \(\theta = 14.5°\).
(b) \(\lambda = 2d\sin\theta = 2 \times 1.0 \times 0.5 = 1.0\,\text{Å} = 0.10\,\text{nm}\).
(c) A tube makes \(0.10\,\text{nm}\) only if its cut-off is at \(0.10\,\text{nm}\) or shorter: \(V \ge 1240/0.10 = 12400\,\text{V} = 12.4\,\text{kV}\).
Values used: \(hc = 1240\,\text{eV nm}\), \(1\,\text{Å} = 0.1\,\text{nm}\).
Molybdenum Kα X-rays, \(0.071\,\text{nm}\), fall on rock-salt planes \(0.282\,\text{nm}\) apart. Find the glancing angle of the first-order reflection, in degrees.
Why does visible light, of wavelength \(500\,\text{nm}\), give no Bragg reflection from a rock-salt crystal?
Bragg's law needs \(\sin\theta = n\lambda/2d\). With \(2d = 0.564\,\text{nm}\), even the first order would need \(\sin\theta = 500/0.564\), about 900, and a sine can never exceed 1. Any wave longer than \(2d\) gives no strong reflection, so visible light is simply transmitted or scattered.
The same law works for any wave. In the chapter on Matter Waves, electrons of \(54\,\text{eV}\) reflected from a nickel crystal by exactly this rule. That is why a crystal proved that electrons are waves, and why it proves the same of X-rays.
Many medicines are sold as tiny crystals. The same molecule can often crystallise in more than one pattern, and the patterns dissolve at different rates in the body. Pharmaceutical laboratories in India check each batch with X-rays. A powder of the medicine gives rings at the Bragg angles of its planes. The set of angles tells which crystal form is present.
In 1954 G. N. Ramachandran and Gopinath Kartha, at the University of Madras, worked on collagen, the protein of skin, tendon and bone. They studied the X-ray pictures of collagen fibres, spot by spot. Each spot came from planes that obey Bragg's law. From the spacings they proposed that collagen is three long chains twisted round one another, a triple helix. The idea proved right. Ramachandran later made a famous chart of the shapes a protein chain can take, still used in every laboratory that studies proteins.
- Measuring \(\theta\) from the normal.Bragg's \(\theta\) is the glancing angle, between the ray and the plane. Subtract the angle from the normal from \(90°\).
- Writing \(d\sin\theta = n\lambda\).The extra path has two pieces, one going in and one coming out: \(2d\sin\theta = n\lambda\).
- Taking equal steps in angle for the orders.The sines go up in equal steps, \(\sin\theta = n\lambda/2d\); the angles do not.
- Forgetting the limit on the order.\(\sin\theta \le 1\), so \(n \le 2d/\lambda\). There are only a few orders, and none if \(\lambda > 2d\).